It should be marked, either on the diode or on the box it came in. If you can't find the mark, then you have to measure it yourself. Take the zener diode, a battery or DC power supply, and a resistor. Wire them all in series, with the NEG (cathode) end of the diode closer to the POSitive side of the battery or power supply. Connect your voltmeter across the diode, and slowlyincrease the power supply output voltage while watching the meter. You'll see the voltage across the diode increase slowly, tracking the power supply, until you reach the Zener voltage. At that point, the voltage across the diode won't increase any more; it'll just stay there at its 'reverse breakdown' voltage, which is the Zener voltage. (If the voltage across the diode goes to around a volt and won't go any higher, the polarity is wrong. Reverse either the diode or else the power supply.) You probably want a wild guess at what the value of the resistor should be. That's difficult to specify if I don't know the power rating of the Zener diode you're testing. I'm going to make the following suggestion completely in the blind: Select the resistor to limit the series current to 30 mA even if you have to crank the power supply up to 50 volts. R = 50/.03 = 1.5 to 2 K-ohms, rated for a couple of watts.
How do you find dia meter of shaft when bearing no is given?
Almost everywhere!!!
Hello, did you ever find the solution manual for this book? please email me wanted_os@hotmail.com
All you have to do is fine a simple task to do and find simple machines and connect them together to make it. All you have to do is fine a simple task to do and find simple machines and connect them together to make it.
the formulas for simple machines help find the ama, ima, and the efficency
A zener diode with a rating of 500 mW will pass 50 mA at 10 V. (Power = voltage times current)Note: The question appears mis stated, in that it states a rating of 500 MW, not 500 mW. To my knowledge, there is no zener with a rating of 500 MW.
It is depend on your requirement .suppose you need a voltage regulator of 5V than you need 5V Zener diode.
A zener diode is like a regular diode when connected in forward bias which means it will control the flow of the electricity throughout the circuit. Usually you'd find a zener diode in a reverse bias mode because of its purpose which is it has a breakdown voltage value of 5.6v; this shows that the circuit output voltage will be regulated at the same value of 5.6v. It also has the ability to change its own internal resistance based current flow passing through it helping sustain a fixed voltage of 5.6v. The benefits of a zener diode are that it is a less cost effective voltage regulator, its simplicity is based on the fact it's a diode with two overall purposes. The main purpose of a zener diode is to maintain a fixed voltage; in order for this to happen it must lower or raise its resistance depending on the actual current flowing throughout the circuit. If the current increases the zener diode will raise the resistance in order to maintain the fixed voltage. If the resistance lowers the diode will raise it because the fixed voltage should be at 5.6v, and works in reversed biased.
The circuit symbol is like a diode, but with short lines coming out of each side of the cathode line, in opposite directions. To find breakdown voltage, find the part code and look it up.
Zener impedance is calculated, like anything else, with Ohm's law. Take voltage and divide by current, and you get resistance (or impedance). The only thing special about a zener is that it is not linear, and you can not expect the impedance to remain the same if you change the voltage or current. In fact, the primary characteristic of a zener is that the voltage is relatively constant over the specified current range so, in effect, the zener is a dynamic resistor or, more correctly, a mostly-independent voltage load.
A zener diode, a transistor, a rectifier diode, and a few resistors. A 10.5V zener diode will conduct until the voltage across it drops to below 10.5. If the relay is small enough, a zener diode is all you need. However, more than likely the current draw of the coil would burn the zener out. Use the zener to drive a transistor, and use the transistor to trigger the relay. V+ | |_______________________ | | _|_| _____|___ |/ \ 10.5V | | /___\ | 3 Relay | __|__ 3 Coil | / \ 3 0---------- /___\ 3 | | | 3 \ \ 4.7K | | / 2.2K / |____ ___| \ \ | / / | | | B | / C | |________|/ | |\ 2N2222 | | \ | | E |______________________| | _|_ \\\ When the voltage is above 10.5V the zener will conduct ant turn on the transistor. The transistor will power the relay. When the voltage drops below 10.5V the zener will stop conducting, shutting off the relay. The rectifier diode absorbs transients caused by the field breakdown in the coil, protecting the transistor. Just a plain resistor will do it or you may follows suggestion and use a computer to do that. The last time i used those ancient devices i find out they operate as a current device like minimum pull in current source. So a passive resistor in series will insure the minimum pull in source however it could be higher then the 10.5 v you need.The above designi just plain silly.
The maximum voltage which can apply When diode in reverse bias..if it is exceed that voltage the diode may get damage.
That is a component for regulating voltage, so in the voltage regulator, unless of course you want to include the ones you would find inside the radio
A Diode will pass the electrical current into one direction, and will produce high resistance in the opposite direction. To check a diode, use an Ohm-Meter or a "multi meter", and set to measure resistance "Ohm", in the 1k Scale. You will have two leads in the ohm meter + and - (Red and Black) If you measure the resistance in one direction ( red lead touching one of the diode leads , and the black is touching the other lead ) , and you found a low resistance in one direction, and a very high resistance in the other direction ( by reversing the red/black leads) , this diode should be ok. If you find low resistance in both directions, this diode is shorted, and is damaged If you find high resistance in both directions, this diode is open circuit, and is damaged
If you want to find it on your own, apply an increasing reverse voltage to the diode until a large current flows. If you do this, put some sort of resistor in series to prevent overload. This will ruin the diode.Or you can check the data sheet. a good search for the particular diode you are using should help, or you can go to the company who sold you the diode and they should have a data sheet readily available. There should be a graph showing reverse current vs. voltage. There should also be a line in the data sheet that says peak reverse voltage which may be easier for you to follow and understand.
There are several types of voltage stabilizer. Older stabilizers utilized relays that automatically broke the current flow when voltage rised above specified level - that was done sequentially with a high frequency. The simplest stabilizer is a Zener diode that is put in parallel, reverse-biased. When supply voltage is too high(greater or equal than diode reverse breakdown voltage) it'll sink excess current. The easiest stabilizers to use in electronics are integrated circuits like common 7805(positive 5 V votage stabilizer). You can find a iagram of its inner circuit in 7805 datasheet at: http://www.datasheetcatalog.org/datasheets/400/249955_DS.pdf
A Transistor can be biassed in two ways Forward bias and Reverse bias A transistor is said to be forward bias if the positive of the transistor is connected to the positive terminal of the battery and negative to the negative terminal of the battery.A Transistor in the converse condition is known as reverse biassed