Sorry i don't know the exact formula but it involves the quantum physics tensorantisymmetric angular momentum operators. it something to do with the ability to generalize advanced mathematics of the universe to arbitrary dimensions i have not tried to do math but i think it just is helicity. angular momentum in 1 dimension simply is a + or a - (and a h-bar/2 constant somewhere i think) that says if its motion is aligned with its spinsor or something. to generalise angular momentum in n-dimensional case is; 1 a + or a - (one level below a scalar) 2 a scalar (just a number with no direction other than + and -) 3 a vector (has direction and value) 4 a tensor (a matrix in this case) that has more than one direction and a value space time geometry or 1 - 3 dimensions a complicated Clifford algebra tensor that i don't want to think of basically in classical mechanics angular momentum is only defined in dimensions of 2 and 3 physicists and mathematicians have generalized it to n-dimensional space but it is not a what you would learn in high school. hope i did OK since i don't even understand all of this but it should at least tell you how complicated it is. try out http:/en.wikipedia.org/wiki/Feynman_checkerboard it is a topic on angular momentum in 1 spacial dimension by some one much smarter than me
Momentum = Mass X Velocity Velocity = Displacement/Time Dimension of Mass = M Dimension of Displacement = L Dimension of Time = T Therefore Dimension of Velocity = LT-1 Therefore Dimension of Momentum = MLT-1
angular velocity (omega) = theta/time taken theta is dimensionless i.e. it has no dimensions therefore, the diemnsion of angular velocity is 1/T=T^-1
Angular momentum is calculated as the product of a rotating object's moment of inertia (I) and its angular velocity (ω). The units of angular momentum are kg m^2/s, which is the same as the units for moment of inertia multiplied by angular velocity (kg m^2 * 1/s). This relationship is based on the principles of rotational motion and conservation of angular momentum.
For the same reason it's not measured in buckets of rotten fish: because those would not be the correct units. Angular momentum is the cross product of the linear momentum and the position vector relative to the center of rotation. If you do a dimensional analysis, you'll see that the proper units are joule-seconds.
The dimensional formula for angular velocity is T-1, where T represents time.
Momentum = Mass X Velocity Velocity = Displacement/Time Dimension of Mass = M Dimension of Displacement = L Dimension of Time = T Therefore Dimension of Velocity = LT-1 Therefore Dimension of Momentum = MLT-1
angular velocity (omega) = theta/time taken theta is dimensionless i.e. it has no dimensions therefore, the diemnsion of angular velocity is 1/T=T^-1
The "intrinsic angular momentum" of particles is commonly called "spin". The spin of a photon is 1, in the units commonly used.
Angular momentum is calculated as the product of a rotating object's moment of inertia (I) and its angular velocity (ω). The units of angular momentum are kg m^2/s, which is the same as the units for moment of inertia multiplied by angular velocity (kg m^2 * 1/s). This relationship is based on the principles of rotational motion and conservation of angular momentum.
The angular momentum quantum number, symbolized by l, indicates the shape of an orbital.
The highest value for orbital angular momentum is determined by the quantum number l, which can range from 0 to (n-1) where n is the principal quantum number. Therefore, the highest value for orbital angular momentum is (n-1)ħ, where ħ is the reduced Planck constant.
For the same reason it's not measured in buckets of rotten fish: because those would not be the correct units. Angular momentum is the cross product of the linear momentum and the position vector relative to the center of rotation. If you do a dimensional analysis, you'll see that the proper units are joule-seconds.
The dimensional formula for angular velocity is T-1, where T represents time.
The term symbol 1D2 specifies the total angular momentum quantum number (L=2) and the azimuthal quantum number for the orbital angular momentum (D type orbital or L=2). It indicates that the atom has an angular momentum of 2 and belongs to the D orbital type in terms of its electron configuration.
case 1 is mass (m) on weightless length (r) of string at constant velocity (v), so angular momentum L = r * (m * v), SI units are n.m.s. or kg.m^2.s^-1 . case 2 is mass(m) rotating around an axis inside its own mass ie solid sphere rotating about its fixed symmetry axis, angular momentum L = I * w, where I is the mass moment of inertia of the sphere about its fixed symettry axis, and w is the rotation in radians per second, units are kg.m^2 for I, and rad / sec for w
The dimension of angular velocity is reciprocal time . . . 1/time or T-1 . It'll be stated as "some angle" per "unit of time", like "45 revolutions per minute", and angles are dimensionless.
The total spin angular momentum of a system of three free electrons can be calculated by adding the individual spin angular momenta of each electron. Since each electron has a spin of 1/2, the total spin angular momentum of the system would be (1/2 +1/2 +1/2) = 3/2.