A power station has an output power of 200MW and 25000Volts what would output be in 1day of operation?

Answer 1

Two equations are needed power = current x potential difference (voltage) and energy = power x time 720kJ = 720 000J 10 mins = 600s Power = 720 000 / 600 = 1200 Watts 1200 = I x 25000 Current, I = 0.048 A

Answer 2

To work out the current flowing through the wires, you use a tree which is Power = Current times the voltages therefore Current is power divided by voltage

this is

0.2/25000 = 0.000008 amps

the reason for this is the higher the voltage the lower the current therefore less energy is lost as heat. which means more electricity reaches the step up Transformers. :)

+++

That looks suspiciously low. I think the questioner meant MW, not mW! (MegaWatts, not milliWatts)

So, assuming output power = 200MW instead and given a transmission voltage = 25kV.

Use indices to deal with all those 10s:

Power = 2 x 10^8 W and Volts = 2.5 X 10^4. (I wish you could use superscripts in Answers!).

Watts = Volts X Amps so I = W/V (The capital letter I, not A, is used to denote the ampere.)

=(2 x 10^8) / (2.5 X 10^4) = (2/2.5) X 10^(8-4) = 0.8 X 10^4 = 8 x 10^3

So a 200MW power-station is sending out a current of 8000A at a voltage of 25kV.

'

A quick test with a calculator - yes 8 000 X 25 000 = 20 000 000! Phew!

In practice I doubt very much that a power-station of anywhere near that rating would send all its output down one line. Also, I'm not sure, but its transmission voltage might be 250kV to divide the current by 10. 8kA is one hell of a current!

Answer 3

The voltage is not relevant. If it gives 200 MW for 24 hours, the output is 4,800 MWh = 4,800,000 KWh

Answer 4

To calculate the total output in one day of operation, you would need to know the duration of operation in hours. Without that information, it is not possible to determine the total output.