A vehicle designed to operate on a drag strip accelerates from zero to 30 ms while under going a straight line path displacement of 45 m?

Answer 1

2ad = Vf^2 - Vi^2
a = (Vf^2 - Vi^2)/2d

a = [(30 m/s)^2 - 0^2]/[2(45m)]
a = 10 m/s^2 answer

Answer 2

The vehicle's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given that the vehicle goes from 0 to 30 m/s in a straight line path displacement of 45 m, you can use the formula of motion: displacement = (initial velocity * time) + (0.5 * acceleration * time^2). Solving these equations will provide you with the acceleration of the vehicle.