Tensions t1 and t2 are related in that they are both forces acting in opposite directions on an object or system. The relationship between t1 and t2 depends on the specific situation and the forces involved.
the frmula for pulley is th weight by its mass
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
To solve Gay-Lussac's Law, use the formula P1/T1 P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Rearrange the formula to solve for the unknown variable.
for the rxn A ---> B, where A is at temp T1 and B at temp T2 1) At constant pressure H1= HB - HA A first converts to B at temp T1 and reh temp rises to T2, thus the heat supplied for this change is Cp(T2-T1), Cp is the heat capacity of products. Hence the heat change will be given by H(path1)= Cp(T2-T1)+H1 2) first the temp of A is raised to T2. the heat supplied for this change is Cp'(T2-T1) , Cp' is the heat capacity of reactants. now A is changed to B with an enthalapy change of H2. H(path2)= Cp'(T2-T1)+H2. H(path1)=H(path2) H2-H1/T2-T1=Cp-Cp'
If you dcrease the temperature you will decrease the pressure proportionately. So, T1 over T2 will equal P1 over P2. We can derive the formula P1 x T2 = P2 x T1. Substitue the values and we get 50.0 mm x 200K = P2 x 540K 10,000 mmK = P2 x 540K 10,000mmK / 540K = P2 P2 = 18.52 mm of Mercury in a constant volume
The CalDigit Thunderbolt™ T1 and T2 primarily differ in that the T1 is a single-drive solution whereas the T2 is a dual-drive solution. See related links for more information.
the frmula for pulley is th weight by its mass
T1/T2=e^(mu*theta)where T1/2 are the tensions in the circlemu is the coefficient of frictiontheta is the angle of the circle in contact with the rope.
COF = h1-h4/h2-h1=T1(s1-s4)/T2-T1(s1-s4)=T1/T2-T1
In NMR spectroscopy, T1 relaxation time is the time it takes for the nuclei to realign with the magnetic field after being disturbed, while T2 relaxation time is the time it takes for the nuclei to lose phase coherence with each other. T1 is related to the recovery of longitudinal magnetization, while T2 is related to the decay of transverse magnetization.
T1 and T2 refer to the first and second thoraxic vertebrae. They are the 8th and 9th vertebrae, starting from the top.
T1 and T2 can refer to the Thoracic vertebrae (part of your spine). But I don't know what 'low' would imply.
The SHLD (Store H&L Direct) instruction takes 5 machine cycles and 16 clock states, not including any wait states. Opcode fetch: T1, T2, T3, and TX Low order address fetch: T1, T2, T3 High order address fetch: T1, T2, T3 Store L: T1, T2, T3 Store H: T1, T2, T3
t1:german tiger 1 t2:german tiger 2 t1:armor 69 t2:armor 89 t1:speed 14 mph t2:speed 20 mph t1:gun is 98% great t2:gun is 99% good so german tiger 2 is better
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
T1= Fat- Appears Bright e.g. Grey matter = Water- Appears Dark e.g. CSF, water T2 Just opposite to T1
Let X(t) be an iid random process and hence X(t) has an identical distribution for any t i.e., distributions are identical at instants of time t1, t2...tn, so 1st order pdfs f(x1;t1), f(x2;t2)....f(xn;tn) are time invariant and further X(t1) and X(t2) are independent for any two different t1 and t2. So, f(x1, x2, . . . , xn; t1, t2, . . . , tn) = f(x1;t1)*f(x2;t2)*....*f(xn;tn) f(x1;t1), f(x2;t2).... f(xn;tn) are time invariant, therefore their product f(x1, x2, . . . , xn; t1, t2, . . . , tn) is also time invariant which is nth order pdf. So X(t) is strict sense stationary.