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An accelerometer measures acceleration by comparing it to the acceleration due to gravity, which is commonly referred to as 1g. By detecting changes in the force exerted on a mass inside the device, an accelerometer can determine the acceleration of an object in terms of multiples of 1g.
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What does 1g feel like when experiencing acceleration?
When experiencing acceleration, 1g feels like the normal force of gravity pulling you down. It is the same feeling as standing on the ground without any additional forces acting on you.
If you were to be accelerated at 1g for one year how far from Earth would you be?
{g represents gravity, which is not a speed and thus cannot be used in calculating rate of acceleration.} ^This incorrect, g IS an acceleration. 1g is 9.8 m/s^2.
An object has a mass of 1g and its volume is 10ml what is the density of the object?
The density of the object is 0.1 g/ml. This is found by dividing the mass (1g) by the volume (10ml).
Why would the terminal velocity of a 1g pellet be higher than that of a 1g piece of paper?
The terminal velocity of an object depends on its size, shape, and mass. A 1g pellet would have a higher terminal velocity than a 1g piece of paper because the pellet is denser and offers less air resistance due to its smaller surface area-to-mass ratio. This allows the pellet to fall faster and reach its terminal velocity sooner than the piece of paper.
What is the uniform acceleration that causes a train velocity to change from 25M's to 75M's in an 5.0period?
As we organize the given data and prepare to calculate, we notice that the gainin speed corresponds to a change from roughly 56 to 168 miles per hour !Acceleration = (change in speed) divided by (time for the change).Acceleration = (75 - 25) / 5.0 = 50/5 = 10 meters per (.....)2The question doesn't give the unit of time represented by the 5.0.If it's 5 seconds, then the acceleration is 10 m/s2 . . . about 2% more than 1G,and a train could never do that.It seems more likely that it's 5 minutes. Then, the acceleration is (1/6) m/s2,or about 0.017G, which is somewhat more reasonable for a mile-long freight.But there's still that problem of winding up at 168 mph.Maybe this is one of those super bullet trains in Germany or Japan that canactually go from 56 to 168 in 5 seconds. This suggests to us that the passengersare probably required to wear seat belts, or at least that they should be.
If an accelerometer reads plus 1g the aircraft is?
When the aircraft is in straight & level flight , accelerometer reads 1g , as the aircraft comes to land on the ground 1g tuns to ZERO
What is the rate of acceleration of earth's center?
Earth's gravitational acceleration is approximately 9.8 m/s^2, or 1g.
What does 1g feel like when experiencing acceleration?
When experiencing acceleration, 1g feels like the normal force of gravity pulling you down. It is the same feeling as standing on the ground without any additional forces acting on you.
If you were to be accelerated at 1g for one year how far from Earth would you be?
{g represents gravity, which is not a speed and thus cannot be used in calculating rate of acceleration.} ^This incorrect, g IS an acceleration. 1g is 9.8 m/s^2.
How do you use accelerometer measure tilt angle?
First, you have to make sure you're measuring the right thing. Tilt isn't specific enough. You'll want to measure pitch and / or roll. Make sure your accelerometer is capable of measuring tilt. Read the datasheets carefully. For example, the ADXL322 is a 2-axis accelerometer which is capable of measuring tilt. The ADXL78 does not repeat NOT have this in the datasheet. You could try to use the 78, but it might not work at all. You must mount the accelerometer so that the sensitive edges are parallel to the ground. In other words, it has to be lying flat on its back. ("How flat?" It must be as flat as you want your accuracy to be. ) In such a configuration, the chip listed above will give pitch as pitch = arcsin( Ax / 1g) and roll as roll = arcsin( Ay / 1g ). Ax and Ay are the two outputs. Read the datasheet. (I can't stress this enough.) While you would usually put the - and + outputs into an instrumentation amplifier, the 322 chip listed above does not have such a thing. You would have to run it through some kind of gain circuit, and probably one with an adjustable gain and offset.
Is 1 G (Acceleration) at 600 Rpm the same as 3 G at 1800 Rpm?
That depends what you want to compare. In any case, 3G is more acceleration than 1G.
Can you beat gravitational acceleration?
Yes, though this could mean many things. Acceleration due to gravity is ~9.81 m/s2 (~35.30394 kph/s), or 1g. Normal cars can't accelerate in a straight line this fast, but race cars can. When you turn a corner, you can accelerate more than 1g. Many things accelerate more than 1g. Particle accelerators accelerate particles at millions of gs. If you are falling, then you can use various forms of propulsion to accelerate faster than 1g. However, without propulsion, it is impossible to accelerate faster than 1g. All you can do is reduce drag, to improve how close to 1g you actually accelerate, and increase your terminal velocity. Escape velocity is the speed you need to be going initially so that the acceleration due to an object (say, the Earth) will never cause you to fall back toward that object. For the Earth (from sea level), that speed is 11.186 km/s (25,022 mph).
How one measure 1g of a liquid?
In a weighting bottle on a laboratory weighting balance (accuracy 0.1 mg).
How many earth g's make up the sun's 274 g's?
Your units are off. Earth's acceleration due to gravity is 9.8 m/s2 = 1g The Sun's acceleration due to gravity is 274m/s2 So you must divide: (274m/s2) / (9.8 m/s2)= 28 times as much gravity on the sun than on earth. Or... the sun's gravity is 28g where 1g is the pull on earth.
Why dont you fall from roller coaster ride when we are upside down?
That is because the roller coaster is designed to accelerate you with enough force to experience more than 1G acceleration. When upside down you are being pulled down with 1G but up with more than 1G so net force is up, not down. Some rides give you 2-3 G up force.
How long does it take to stop from 65 mph?
You need to know one other thing to answer this question. The acceleration of the braking. The formula is: t=v/a where t is the time, a is the acceleration and v is velocity. For example, in a regular car, to stop from 65 mph (95.3 ft/sec) at a deceleration of 1G (32 feet per second²) would take 2.98 seconds. Incidentally, it would take 142 feet to stop ( formula s=½at² where s is distance).I assumed you are asking this as it relates to a car. 1G is a very good average braking acceleration for a car.
Is the iPod 1g the same as iPod first generation?
1g is not the same as 1st gen. there's no 1g ipods.
