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How does an accelerometer measure acceleration in terms of 1g?
An accelerometer measures acceleration by comparing it to the acceleration due to gravity, which is commonly referred to as 1g. By detecting changes in the force exerted on a mass inside the device, an accelerometer can determine the acceleration of an object in terms of multiples of 1g.
If you were to be accelerated at 1g for one year how far from Earth would you be?
{g represents gravity, which is not a speed and thus cannot be used in calculating rate of acceleration.} ^This incorrect, g IS an acceleration. 1g is 9.8 m/s^2.
Why do you feel light coming down a hill on a roller coaster?
The same thing happens if you are coming down in an elevator, or if you fall from any height. If you are standing still on the ground, you are subjected to gravity from the Earth which is effectively an acceleration of 1g or about 9.81 metres per second squared and you will feel your normal weight. If you fall from a height you will accelerate towards the ground at about 9.81 metres per second squared and you will feel "light" or indeed "weightless". On the downward hill of a rollercoaster, the rate of descent is enough to make you feel lighter than usual and similarly, on the upward hill of a rollercoaster the rate of ascent might be enough to make you feel heavier than usual. The design of the rollercoaster determines just how much lighter you will feel on the downward sections. You can try a neat little experiment if you take a set of ordinary bathroom scales with you into an elevator. You should observe that you "weigh more" when the elevator accelerates upwards and that you "weigh less" when the elevator accelerates downwards.
An object has a mass of 1g and its volume is 10ml what is the density of the object?
The density of the object is 0.1 g/ml. This is found by dividing the mass (1g) by the volume (10ml).
Why would the terminal velocity of a 1g pellet be higher than that of a 1g piece of paper?
The terminal velocity of an object depends on its size, shape, and mass. A 1g pellet would have a higher terminal velocity than a 1g piece of paper because the pellet is denser and offers less air resistance due to its smaller surface area-to-mass ratio. This allows the pellet to fall faster and reach its terminal velocity sooner than the piece of paper.
How does an accelerometer measure acceleration in terms of 1g?
An accelerometer measures acceleration by comparing it to the acceleration due to gravity, which is commonly referred to as 1g. By detecting changes in the force exerted on a mass inside the device, an accelerometer can determine the acceleration of an object in terms of multiples of 1g.
What is the rate of acceleration of earth's center?
Earth's gravitational acceleration is approximately 9.8 m/s^2, or 1g.
How far must an object weighing 10 gsmfall to register 1G when it hits the ground?
Sounds like a trick question. Everything that's sitting on the ground is experiencing 1G w/o falling any distance at all.
If you were to be accelerated at 1g for one year how far from Earth would you be?
{g represents gravity, which is not a speed and thus cannot be used in calculating rate of acceleration.} ^This incorrect, g IS an acceleration. 1g is 9.8 m/s^2.
Is 1 G (Acceleration) at 600 Rpm the same as 3 G at 1800 Rpm?
That depends what you want to compare. In any case, 3G is more acceleration than 1G.
When might you feel a force less than 1g?
At high altitude.
If you are travelling near to the surface of Earth vertically upwards at a constant velocity how much g force would you feel 1g or some value dependent on the velocity and how do you calculate it?
A direct answer is that the voyager in the question is going to be experiencing 1g of acceleration due to gravitational effect regardless of velocity. And that's all. Here's why. We didn't see our traveler lift off. That's where he gets smooshed back in his seat. That's not part of the question. We are joining him in flight where he is moving vertically at some velocity which, though it wasn't quantified, was specified as constant. The key is the constant velocity. That means no vertical acceleration from the rocket. No vertical acceleration from the rocket and only gravity pulling down means the effect of gravity has zero help from the rocket in smooshing our traveler back in his seat, so he is experiencing 1g of acceleration, and all of it due to gravity. To see another view, apply magic. Picture the rocket moving along horizontally like a car cruising down a highway. (Magic, remember? Picture it.) The rocket is moving at a fixed speed. Is the traveler being pushed back in his seat? Would the traveler in a car be pushed back in his seat if traveling at a fixed speed down a road regardless of speed? No, he wouldn't. Neither is our traveler in his rocket. Now more magic. Instantly (in zero time) our traveler's rocket is traveling up at the same (unspecified) fixed speed. (No turning, just instantaneous change of direction.) The only thing that has changed is direction. Oh, and gravity is now pulling down on our traveler at an amount based on his mass and not on the change of speed of the rocket. There is no acceleration component due to the rocket changing speed. The only acceleration our traveler is experiencing is due to gravity, and that will be 1g of down force. Regardless of the velocity.
Can you beat gravitational acceleration?
Yes, though this could mean many things. Acceleration due to gravity is ~9.81 m/s2 (~35.30394 kph/s), or 1g. Normal cars can't accelerate in a straight line this fast, but race cars can. When you turn a corner, you can accelerate more than 1g. Many things accelerate more than 1g. Particle accelerators accelerate particles at millions of gs. If you are falling, then you can use various forms of propulsion to accelerate faster than 1g. However, without propulsion, it is impossible to accelerate faster than 1g. All you can do is reduce drag, to improve how close to 1g you actually accelerate, and increase your terminal velocity. Escape velocity is the speed you need to be going initially so that the acceleration due to an object (say, the Earth) will never cause you to fall back toward that object. For the Earth (from sea level), that speed is 11.186 km/s (25,022 mph).
How many earth g's make up the sun's 274 g's?
Your units are off. Earth's acceleration due to gravity is 9.8 m/s2 = 1g The Sun's acceleration due to gravity is 274m/s2 So you must divide: (274m/s2) / (9.8 m/s2)= 28 times as much gravity on the sun than on earth. Or... the sun's gravity is 28g where 1g is the pull on earth.
Why dont you fall from roller coaster ride when we are upside down?
That is because the roller coaster is designed to accelerate you with enough force to experience more than 1G acceleration. When upside down you are being pulled down with 1G but up with more than 1G so net force is up, not down. Some rides give you 2-3 G up force.
How long does it take to stop from 65 mph?
You need to know one other thing to answer this question. The acceleration of the braking. The formula is: t=v/a where t is the time, a is the acceleration and v is velocity. For example, in a regular car, to stop from 65 mph (95.3 ft/sec) at a deceleration of 1G (32 feet per second²) would take 2.98 seconds. Incidentally, it would take 142 feet to stop ( formula s=½at² where s is distance).I assumed you are asking this as it relates to a car. 1G is a very good average braking acceleration for a car.
Is the iPod 1g the same as iPod first generation?
1g is not the same as 1st gen. there's no 1g ipods.
