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A boy pushing forward on a crate with a force of 100 newtons the reaction force is?
The reaction force is 100 newtons exerted by the crate on the boy in the opposite direction (Newton's third law).
How much work in joules is performed when a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 meters?
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
The friction force exerted on the crate by the floor is equal in magnitude but opposite in direction to the pushing force you apply to the crate. If the crate is not moving, the friction force is static friction, and it adjusts its magnitude to exactly match the applied force to keep the crate at rest.
A crate is pulled across a horizontal floor by a rope At the same time the crate pulls back on the rope in accord with Newton's 3rd law Does the work done on the crate by the rope then equal zero?
No, the work done on the crate by the rope is not zero. The work done is equal to the force exerted by the rope multiplied by the distance the crate is pulled. The fact that the crate pulls back on the rope in accordance with Newton's Third Law does not cancel out the work done by the rope.
A boy pushing forward on a crate with a force of 100 newtons the reaction force is?
The reaction force is 100 newtons exerted by the crate on the boy in the opposite direction (Newton's third law).
How much work in joules is performed when a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 meters?
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
The friction force exerted on the crate by the floor is equal in magnitude but opposite in direction to the pushing force you apply to the crate. If the crate is not moving, the friction force is static friction, and it adjusts its magnitude to exactly match the applied force to keep the crate at rest.
A crate is pulled across a horizontal floor by a rope At the same time the crate pulls back on the rope in accord with Newton's 3rd law Does the work done on the crate by the rope then equal zero?
No, the work done on the crate by the rope is not zero. The work done is equal to the force exerted by the rope multiplied by the distance the crate is pulled. The fact that the crate pulls back on the rope in accordance with Newton's Third Law does not cancel out the work done by the rope.
As you increase your push will friction on the crate increase also?
Yes, as you increase the force exerted by pushing the crate, friction between the crate and the surface will also increase. This is because friction is directly proportional to the normal force between the surfaces and the coefficient of friction. More force results in a greater normal force, leading to increased friction.
A 1500 N crate is being pushed across a level floor at a constant speed. What will be the acceleration of the crate?
The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.
When you push a crate with N across a M floor how much work is done?
The work done when pushing a crate with a force N across a distance M on a floor depends on the angle between the force and the direction of motion. If the force is applied in the same direction as motion, work done is N * M. If the force is applied at an angle, work done is N * M * cos(theta), where theta is the angle between the force and direction of motion.
When a person pushes a crate across the floor what is the effect?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
How much work did the movers do horizontally pushing a 150 kg crate 10.4 m across a rough floor without acceleration if the effective coefficient of friction was 0.70?
The work done by the movers can be calculated using the work-energy principle. The work done can be found by multiplying the force of friction by the distance the crate was moved. The force of friction is the product of the coefficient of friction and the normal force (weight of the crate). The work done will be equal to the force of friction multiplied by the distance moved.
How do you get the three cubes to get the button in snowpeak in Zelda twilight princess?
The first time you enter the room. Start by pushing the crate in the southeast corner across to the southwest. Then push the crate in the northwest corner across the room so it toches the iced crate. Stand behind the crate you just pushed and push it to the south. Then push the same crate westone space so it hits the first crate. Now push the crate one more time south and the switch will be activated. The second time you need to enter the room is different. start by pushing the crate to the north south. Go to the south and shove the crate to the middle of the puzzle so it passes over the middle floor switch. Now shove the crate that's on the eastern edge west then north. So Its sitting in front of the middle floor switch. Run to the crate that's furthest north and push it clockwise around the rim of the puzzle so it hits the crete you have yet to move. Finally face north and push the crate so it is on the switch leading upstairs.
What is the force of friction acting on a crate that slides across the floor?
The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.
