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as a voltage is applied across a capacitor charges accumulate on the plates.due to accumulation of charges,electric field between the plates develop in the direction opposite to the applied field.this field give rise to the potential across the plates.if the plates get completely charged due to the applied voltage i.e if the whole of the charge q=c(capacitance of the capacitors)xv(voltage applied) develops on the plates,then the applied voltage wiil be opposed to an extent that no further charges will induce on it.But in practice,it takes very long time for the capacitor to get completely charged due to the applied voltage..............now coming to ac circuits,having capacitor.......if the frequency of ac applied voltage is less then the voltage will change slowly.due to this at each instant large amount of charge will develop on the plates causing large opposition.vice versa to high frequency applied voltage.
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What is the relationship between capacitor current and voltage in an electrical circuit?
The relationship between capacitor current and voltage in an electrical circuit is that the current through a capacitor is directly proportional to the rate of change of voltage across it. This means that when the voltage across a capacitor changes, a current flows to either charge or discharge the capacitor. The relationship is described by the equation I C dV/dt, where I is the current, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
How does the voltage across a capacitor change over time when a current is flowing through it?
When a current flows through a capacitor, the voltage across it increases or decreases depending on the rate of change of the current. If the current is constant, the voltage remains steady. If the current changes rapidly, the voltage across the capacitor changes quickly as well.
How do you plot current vs time graph of capacitor?
To plot a current vs. time graph for a capacitor being charged, you would typically see the current start high and decrease as the capacitor charges up. The rate of decrease in current depends on the capacitance and the resistance in the circuit. To analyze this, you can use the formula for charging a capacitor: I = C(dV/dt), where I is the current, C is the capacitance, and dV/dt is the rate of change of voltage across the capacitor.
How can one determine the direction of induced current in a circuit?
The direction of induced current in a circuit can be determined using Lenz's Law, which states that the induced current will flow in a direction that opposes the change in magnetic field that caused it. This means that the direction of the induced current will be such that it creates a magnetic field that opposes the original change in magnetic field.
How does the current from a charged capacitor light a bulb, and how does the brightness of the bulb change as time goes on?
When a charged capacitor is connected to a light bulb, the current flows from the capacitor through the bulb, causing it to light up. Initially, the bulb may be very bright as the capacitor discharges quickly, but as time goes on, the brightness decreases as the capacitor loses its charge and the current flowing through the bulb decreases.
Why capacitor oppose change in voltage and allows current to flow?
Because that is what a capacitor does, resist a change in voltage. It holds a certain amount of energy per charge (voltage), and to change that voltage requires current proportionally to the capacitance.
What is the electrical property that opposes change in current?
inductance
What is the difference between an inductor and a capacitor?
Firstly the suffix '-ance' in each of those three words indicate the properties the material exhibits. Therefore resistance is the property by which any material tends to oppose the flow of current through it. Inductance is the property by which a material opposes the change in current, or opposes an alternating current. An inductor can be appreciated simply using a coil of insulated wire, or a solenoid. Capacitance is the property by which a material opposes the change in voltage across its ends, ie how it opposes alternating voltage. A capacitor comprises of, essentially, two metallic plates separated by a dielectric (a medium which may/may not be non-conducting, but is capable to contain charge). cheers!!
What is the relationship between capacitor current and voltage in an electrical circuit?
The relationship between capacitor current and voltage in an electrical circuit is that the current through a capacitor is directly proportional to the rate of change of voltage across it. This means that when the voltage across a capacitor changes, a current flows to either charge or discharge the capacitor. The relationship is described by the equation I C dV/dt, where I is the current, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
Did capacitor allow change in current?
capacitors allow ac current to flow.
How does the voltage across a capacitor change over time when a current is flowing through it?
When a current flows through a capacitor, the voltage across it increases or decreases depending on the rate of change of the current. If the current is constant, the voltage remains steady. If the current changes rapidly, the voltage across the capacitor changes quickly as well.
What is the value of capacitor voltage and current after 5 time constant?
After 5 time constants, capacitor voltage/current will be about 99.3% of the input step change.
Why does the current lead the voltage across a capacitor by 90 degree rather than lag it?
A: Because a capacitor have to have time to charge to the voltage In a capacitor, the current depends on the voltage difference across it. On AC, this makes it charge, if the voltage is increasing above zero, and discharge if the voltage is reducing towards zero. Because a capacitor has almost no internal resistance, and most loads that it is connected to have only very small resistances in series with the capacitor, the charging and discharging currents depend pretty much on the rate at which the voltage is changing. At the zero crossing point of the sine-wave, when the voltage is actually zero, the rate of change of voltage is very high (the sine-wave is at its steepest), so the current is also very high. If the voltage is positive-going, the current is positive, and if the voltage is negative-going, the current is negative. At the peak of the voltage waveform, the rate of change of voltage is zero or very low (the sine-wave is flat, and not really changing its voltage) so the current is zero, too. Since the maximum positive current occurs when the voltage is passing through zero, going positive, and the maximum negative current happens when the voltage is passing through zero, going negative, the current peaks happen 90 degrees before the voltage peaks, so the current is said to lead the voltage. This is the same as saying the voltage lags the current by 90 degrees.
A capacitor opposes a change in?
Capacitors charge by transferring charge from one plate to the other. This is not the same as a battery, though it can seem so. They oppose a change in voltage because the two plates are close to each other, separated by the dielectric, and the transfer of charge requires current. Once charged, however, the current becomes zero. The differential equation describing a capacitor is dv/dt = i/c, or volts per second = current over capacitance.
What are the cause of induced emf?
A change in current causes a voltage to be induced into an inductive circuit, which opposes that change of current. This is because the change in current is accompanied by a change in magnetic flux which 'cuts' the conductors and induces a voltage into them.
How do you plot current vs time graph of capacitor?
To plot a current vs. time graph for a capacitor being charged, you would typically see the current start high and decrease as the capacitor charges up. The rate of decrease in current depends on the capacitance and the resistance in the circuit. To analyze this, you can use the formula for charging a capacitor: I = C(dV/dt), where I is the current, C is the capacitance, and dV/dt is the rate of change of voltage across the capacitor.
How can one determine the direction of induced current in a circuit?
The direction of induced current in a circuit can be determined using Lenz's Law, which states that the induced current will flow in a direction that opposes the change in magnetic field that caused it. This means that the direction of the induced current will be such that it creates a magnetic field that opposes the original change in magnetic field.
