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How does the current from a charged capacitor light a bulb, and how does the brightness of the bulb change as time goes on?
When a charged capacitor is connected to a light bulb, the current flows from the capacitor through the bulb, causing it to light up. Initially, the bulb may be very bright as the capacitor discharges quickly, but as time goes on, the brightness decreases as the capacitor loses its charge and the current flowing through the bulb decreases.
What else can I help you with?
How do you plot current vs time graph of capacitor?
To plot a current vs. time graph for a capacitor being charged, you would typically see the current start high and decrease as the capacitor charges up. The rate of decrease in current depends on the capacitance and the resistance in the circuit. To analyze this, you can use the formula for charging a capacitor: I = C(dV/dt), where I is the current, C is the capacitance, and dV/dt is the rate of change of voltage across the capacitor.
What is the relationship between capacitor current and voltage in an electrical circuit?
The relationship between capacitor current and voltage in an electrical circuit is that the current through a capacitor is directly proportional to the rate of change of voltage across it. This means that when the voltage across a capacitor changes, a current flows to either charge or discharge the capacitor. The relationship is described by the equation I C dV/dt, where I is the current, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
How does the voltage across a capacitor change over time when a current is flowing through it?
When a current flows through a capacitor, the voltage across it increases or decreases depending on the rate of change of the current. If the current is constant, the voltage remains steady. If the current changes rapidly, the voltage across the capacitor changes quickly as well.
How capacitor opposes the change in current?
as a voltage is applied across a capacitor charges accumulate on the plates.due to accumulation of charges,electric field between the plates develop in the direction opposite to the applied field.this field give rise to the potential across the plates.if the plates get completely charged due to the applied voltage i.e if the whole of the charge q=c(capacitance of the capacitors)xv(voltage applied) develops on the plates,then the applied voltage wiil be opposed to an extent that no further charges will induce on it.But in practice,it takes very long time for the capacitor to get completely charged due to the applied voltage..............now coming to ac circuits,having capacitor.......if the frequency of ac applied voltage is less then the voltage will change slowly.due to this at each instant large amount of charge will develop on the plates causing large opposition.vice versa to high frequency applied voltage.
What is the function that describes the current through a capacitor as a function of time?
The function that describes the current through a capacitor as a function of time is given by the equation I(t) C dV/dt, where I(t) is the current at time t, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
How do you plot current vs time graph of capacitor?
To plot a current vs. time graph for a capacitor being charged, you would typically see the current start high and decrease as the capacitor charges up. The rate of decrease in current depends on the capacitance and the resistance in the circuit. To analyze this, you can use the formula for charging a capacitor: I = C(dV/dt), where I is the current, C is the capacitance, and dV/dt is the rate of change of voltage across the capacitor.
Why capacitor oppose change in voltage and allows current to flow?
Because that is what a capacitor does, resist a change in voltage. It holds a certain amount of energy per charge (voltage), and to change that voltage requires current proportionally to the capacitance.
What is capacitive effect in antenna?
The capacitive effect is an element's opposition to a change in AC voltage. The resistor will develop a positively charged current at it flows through a capacitor. This will prevent a change in the initial voltage.
Why don't capacitor discharge completely in an RC circuit?
Capacitors do not get "full" like a glass of water. The current into a capacitor is the rate of change of charge, so it's equal to C * dV/dt or something. If the voltage is constant, there's no current. If the voltage on both sides of the resistor is the same, there's no current through the resistor and hence into the capacitor, so that's the steady-state - what you call "full" - the capacitor charged to the supply voltage.
What is the relationship between capacitor current and voltage in an electrical circuit?
The relationship between capacitor current and voltage in an electrical circuit is that the current through a capacitor is directly proportional to the rate of change of voltage across it. This means that when the voltage across a capacitor changes, a current flows to either charge or discharge the capacitor. The relationship is described by the equation I C dV/dt, where I is the current, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
Did capacitor allow change in current?
capacitors allow ac current to flow.
Why does a fully charged capacitor show infinite resistance?
The voltage-current relationship for a capacitor is i = C dv/dt, where i is the current flowing through, C is the capacitance and dv/dt is the time rate change of the voltage across that capacitor. So, when a capacitor is fully charged, the voltage no longer changes with time (the derivative, dv/dt, is now 0). As can be seen from the equation, the current would therefore be 0. Anything with 0 current flowing through is an open circuit, and can be treated like a resistor with infinite resistance (in models, anyway). Practically speaking, capacitors aren't this perfect, but you will still have an extremely high resistance once fully charged (voltage changes negligibly after charging).
How does the voltage across a capacitor change over time when a current is flowing through it?
When a current flows through a capacitor, the voltage across it increases or decreases depending on the rate of change of the current. If the current is constant, the voltage remains steady. If the current changes rapidly, the voltage across the capacitor changes quickly as well.
What is the value of capacitor voltage and current after 5 time constant?
After 5 time constants, capacitor voltage/current will be about 99.3% of the input step change.
What does the continuity of capacitor voltage mean?
It might mean that the voltage across a capacitor cannot change instantanteously because that would demand an infinite current. The current in a capacitor is C.dV/dt so with a finite current dV/dt must be finite and therefore the voltage cannot have a discontinuity.
Why don't capacitors allow DC current to pass?
A capacitor allows AC (to pass through) because capacitors resist a change in voltage.. The capacitor need change resist in Input signal
How capacitor opposes the change in current?
as a voltage is applied across a capacitor charges accumulate on the plates.due to accumulation of charges,electric field between the plates develop in the direction opposite to the applied field.this field give rise to the potential across the plates.if the plates get completely charged due to the applied voltage i.e if the whole of the charge q=c(capacitance of the capacitors)xv(voltage applied) develops on the plates,then the applied voltage wiil be opposed to an extent that no further charges will induce on it.But in practice,it takes very long time for the capacitor to get completely charged due to the applied voltage..............now coming to ac circuits,having capacitor.......if the frequency of ac applied voltage is less then the voltage will change slowly.due to this at each instant large amount of charge will develop on the plates causing large opposition.vice versa to high frequency applied voltage.
