Least count of voltmeter is the value of one division on the scale.
Formula is: Least count = Range/No. of divisions
For example, if a voltmeter can measure from 0 to 40 V, and it has 100 divisions in total on the scale, then its least count is 40/100 = 0.4V
the least count of ammeter and voltmeter should be less.....because the lesser value of LC will lead us to a more precise measurement.
if there are 20 divisions between 0 to0.5 least count is 0.5/20
zerro error in a spring balance affects the accuracy in the weight. To find zero error in spring balance, you have to first find the least count of the spring balance and then suspend it freely, if the outcome is +1, the zero error is +1 and if it is -1 ,the zero error is -1.
It is a wrist watch that shows seconds. You count the pulses in the wrist for 30 seconds, then double the count to find the number of beats for a full minute.
You have to find the LC (the least countable) of the tool.
Wow! I guess we'd have to test that one. As soon as you find a virtual object to work with, you can count me in.
Start by measuring accurately, then just remove digits until you have the precision you want.
Connect ammeter in series and voltmeter in parallel to the circuit
we can measure the resistance of the motor by using voltmeter ammeter method of by directly using a multimeter across the armature terminals of the motor in voltmeter ammeter method we should use a less value of dc voltage to find the resistance
Generally electronics meters may be ammeter Or Voltmeter. So for measuring the components Value We use a small small circuits . Ex :- to measuring the value of Resistor we supply voltage acroo it & add a Ammeter to measuring the Current thats why we can find value of resistance using Ohm's Law.
I am going to assume that you mean low "resistance" in an open circuit test and are performing this with a multimeter. An ammeter works by place a very small amount of resistance in series with a circuit and then measuring the Voltage drop across the resistance. The Voltage is directly proportional to the current as given in ohms law: E = I x R If you are measuring the resistance through the ammeter it will have a very low resistance and impedance.
If lights randomly go off, there is likely a wiring issue. Using a voltmeter or ammeter may find a break in the wire or a short circuit of some kind. A fuse could also be loose.
LC= S over N
By using an Ammeter in series
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
first find out least count of main circular scale in degrees,then divide least count of main scale by total divisions on cylindrical scale(this cylindrical scale works as vernier scale for fist one,its least count will be in minutes) then further divide least count of cylindrical scale by total divisions of small vernier scale which touches it,(this small scale works as vernier scale for cylindrical scale and its least count will be in seconds).
Electric current is measured using an instrument called an ammeter. The SI unit of measurement for current is the ampere, which is defined in terms of the force between parallel, current-carrying, conductors due to the interaction of their magnetic fields.
Total number of mine scale and devided by thumbl scal
There are several ways of doing this, but it depends on what information you have to start with. One way is to find the impedance, using a voltmeter and an ammeter (impedance will be the product of the two readings), and the resistance using an ohmmeter (or, better still, a Wheatstone Bridge) and, then, use the equation:cos (phase angle) = resistance / impedance