We can find the velocity after 8 seconds using the equation v = v0 + at, so
v = 0 + (9.8)(8), v = 78.4. We can then use the equation v2 = v02 + 2ax to find how far it will fall:
78.42 = 02 + 2(9.8)x
x = 78.42/(2*9.8) = 313.6
The object will fall about 313.6 meters.
(Your final answer may differ a little due to rounding differences.)
In the first six inches a falling object travels six inches.
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Another contributor added some background:
According to most of the evidence that has been collected in physical and mechanical
mensuration laboratories throughout most of the twentieth Century, a definite pattern
has begun to emerge. We can now say with some assurance that to the limits of the
most modern techniques of observation, if Newton's Laws are accurate and the
relativistic contractions and dilatations are small enough to be ignored, then we can
even include the effects of air resistance ... an encouraging confirmation of the underlying
theory ... and state with a high degree of confidence that the answer to the question is:
Precisely six inches.
s=?
u=0
t=6
a=9.8
s=ut+1/2at^2
s-1/2*(4.9)*6^2
Falls 88.2 meters
s=ut+1/2 at^2
so if your u=0
s=1/2*a*t^2=1/2*9.8*9*9=396.9m
78.46 meters (257.4 feet)
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
2997923580 m or 9835710564 ft
Assuming the object free-falls, we may use:x = x0 + v0t + at2/2x0 = 0 (we determine it)v0t = 0 (dropped from rest).a = g = 10 m/st2 = 16s2.x = 10*16 / 2 = 80m.
When objects are far away, the distance of the object is much greater than the distance that you are moving. Hence, there is little change in the relative position of you and the object.
78.46 meters (257.4 feet)
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
320 meters
The answer is 91 ft, of course!
(25 meters per second) x (1.5 seconds) = 37.5 meters
That would be distance.
122.5 meters (402.5 feet)
576 feet
2997923580 m or 9835710564 ft
Assuming the object free-falls, we may use:x = x0 + v0t + at2/2x0 = 0 (we determine it)v0t = 0 (dropped from rest).a = g = 10 m/st2 = 16s2.x = 10*16 / 2 = 80m.
1.8 m
If it's falling near the earth's surface, the weight is 27.56 pounds (rounded), regardless of how long or how far it's been falling.