To reach a height of 12m, the initial velocity of the ball when thrown upward must be at least 8 m/s, assuming no air resistance and disregarding other factors like wind, drag, etc. This calculation is based on the kinematic equation: (v^2 = u^2 + 2as), where (v) is the final velocity (0 m/s at the peak), (u) is the initial velocity, (a) is the acceleration due to gravity (-9.81 m/s(^2)), and (s) is the displacement (12m).
The height reached by a ball thrown upward depends on its initial speed: the higher the initial speed, the higher the maximum height reached. This is because a greater initial speed gives the ball more kinetic energy, allowing it to overcome gravity and reach a higher position before gravity brings it back down.
The velocity of the ball is 16 feet/sec when it is thrown upward.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
If the height from which the ball is thrown is increased, the time of flight of the ball would increase as well. This is because the initial velocity of the ball would be higher, leading to a longer time for the ball to reach the ground.
The height reached by a ball thrown upward depends on its initial speed: the higher the initial speed, the higher the maximum height reached. This is because a greater initial speed gives the ball more kinetic energy, allowing it to overcome gravity and reach a higher position before gravity brings it back down.
The velocity of the ball is 16 feet/sec when it is thrown upward.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
If the height from which the ball is thrown is increased, the time of flight of the ball would increase as well. This is because the initial velocity of the ball would be higher, leading to a longer time for the ball to reach the ground.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
OW! Not long enough!
The initial velocity of the ball thrown upward at 16 ft per second is 16 ft/s.
The velocity of a ball thrown upward at 16 ft/sec would be 16 ft/sec when it leaves the hand, but it will decrease due to gravity as it moves upward.
A ball thrown upward returns to its point of projection due to the force of gravity acting on it. Gravity continuously pulls the ball back towards the Earth, causing it to eventually reach its original point of release. This process is governed by the laws of physics related to gravity and projectile motion.
The only constant when a ball is thrown upward is the acceleration due to gravity acting in the opposite direction to the velocity of the ball. Other factors, such as air resistance and the initial velocity of the ball, may change as the ball moves.
A ball thrown upward is not considered a free falling body because it initially moves against gravity. Free falling bodies accelerate downward due to gravity alone, while a ball thrown upward has an initial velocity in the opposite direction.