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Q=m⋅c⋅ΔT

where:

m is the mass of the substance (in grams),

c is the specific heat capacity of the substance (in cal/°C·g),

Δ

ΔT is the change in temperature (in °C).

In this case, for iron:

=

33.1

m=33.1 grams,

=

0.108

c=0.108 cal/°C·g,

Δ

=

48

17

=

31

ΔT=48−17=31 °C.

Now, plug these values into the formula:

=

33.1

g

0.108

cal/°C

\cdotp

g

31

°C

Q=33.1g⋅0.108cal/°C\cdotpg⋅31°C

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Related Questions

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