Moles=given wt./molecular weight
1.25=given wt./70
given wt.=70*1.25=87.5 gm
If by "p" you mean phosphorous (atomic symbol P - the upper case letter, not the lower case letter) then 1.5 moles would correspond to 1.5x30.973762 grams = ~46.465 grams.
1.5 moles P x 30.97g / mole = 46.455g
Watch your sig figs!! =P
1/31 = 0.03226
46.5
0.125 mole
one ritz cracker equals 3 grams therefore you will need 5 ritz crackers which will equal 15g but it's close enough :P
The average weight of a tshirt is 150 grams, so with that in mind, a dress shirt, depending on the material should range from around 250-900g. This is a guess though, im in the same dilema trying to calculate p&p!
Well that depends, do you think 0.79 grams is high? Compared to water, which has a density of 1.0 grams.. so does alcohol have a high density compared to water? No. :P
On the assumption you are referring to gasses; pV = nRT where p = pressure, V = volume, n = number of moles of gas, R = universal gas constant, T = temperature in Kelvin. You would have to convert mass into the number of moles of gas by dividing mass by the relative molecular mass of the gas. Then, rearranging the above gives V = (nRT / p).
2.3 grams P (1mole P/30.97 grams) = 0.07427 moles Phosphorous 0.07427 moles P * 6.022 X 10^23 = 4.5 X 10^22 atoms of P in 2.3 grams P 4.5 X 10^22/6.022 X10^23 = 0.07427 moles of atoms in 2.3 grams of phosphorous
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
Say you have 100 grams of the compound. If so, then you would have 3.1 grams H, 31.5 grams P, and 65.4 grams O. Convert these to moles: 3.1 grams H ÷ 1.01 grams/mol = 3.07 moles H 31.5 grams P ÷ 31.0 grams/mol = 1.02 moles P 65.4 grams O ÷ 16.0 grams/mol = 4.09 moles O Divide each of these by the smallest number, which is 1.02: 3.07 ÷ 1.02 = 3 1.02 ÷ 1.02 = 1 4.09 ÷ 1.02 = 4 These are your ratios. The empirical formula is then H3PO4
There are 2.04 vaginas in a mole so techinically speaking there 5 7 moles in your moms vagina! which mean thats 7 moles will die from lack of food! which they will then weigh .6grams each. So 7 times 2.04 vaginas is 14.28 moles. Then you take 14.28 moles times .6 grams which equals sperm! :P
0.125 mole
1000
grams is weight - cups is volume.
This can be simplified to -10p = -150 p = -150/-10 p = 15
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
hummm 40? just maybe........ yeah not sure tho ;p
1 mole Zn3(PO4)2 (2 moles P/1 mole Zn3(PO4)2) 2 moles phosphorous ===============