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What is made when matter and antimatter collide?
They annihilate each other, releasing a relatively large quantity of energy, which can be calculated using the formula e=mc2, where e is the released energy in joules, m is the mass of the particles in kilograms, and c is the speed of light in metres per second
What is the law of matter and antimatter?
Sir Issac Newton had three laws of motion, which all concerned matter. The first was the law of inertia: an object is either still or moving at a constant speed, and will stay either moving or at the same speed unless acted on by an external force (such as friction - this is why you cannot slide forever on concrete). The second was the law of force: F=m*a (where F=force, M=mass, and a=acceleration). The third was the law of conservation of energy: for every action, there is an equal and opposite reaction (this is why, if you push off of the floor with your feet, you will go up - commonly known as jumping).
What is the power output of the anti-matter reactor?
This question presupposes the existence of an antimatter reactor. As far as I know, no such reactor exists, or has even been designed. Antimatter reacts with matter to produce energy with virtually no matter remaining. Such a reaction is thousands of times more powerful as nuclear reactions we have used on this planet. But antimatter is difficult to make and nearly impossible to handle. As soon as it touches anything, it is gone. There is a lovely quote from a researcher who has made antimatter often. He said that if all the antimatter made at CERN were put together and reacted with matter, the resulting energy would power a light bulb for a few seconds. This even though it is the most powerful reaction we know of. There just is not enough of it to react usefully.
How much NH3 is needed to react exactly with 21 grams of CH3OH?
To calculate the amount of NH3 needed to react with 21 grams of CH3OH, you first need to balance the chemical equation for the reaction. Then, you convert the mass of CH3OH to moles and use the mole ratio from the balanced equation to determine the moles of NH3 required. Finally, convert the moles of NH3 to grams using the molar mass of NH3.
How many grams of bromine are required to completely react with 22.1 g of titanium?
The molar mass of titanium is 47.87 g/mol and the molar mass of bromine is 79.90 g/mol. Titanium reacts with two moles of bromine, so you would need 2 moles of bromine per mole of titanium. Using the molar masses of both elements, you can calculate the grams of bromine needed to react with 22.1 g of titanium.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many grams of are needed to react with 3.18 of?
cannot answer without more info.
How many grams of silver nitrate are needed to react with 50 grams of sodium chloride?
You need 145,337 g silver nitrate.
How many grams of water are needed to react with 73.0 g CaCN2?
mass H2O =49.2g
If you start with 32 grams of CH4 and react it with O2 to form 88 grams CO2 and 72 grams H2O. How much O2 in grams was consumed?
128 g of oxygen are needed.
What is made when matter and antimatter collide?
They annihilate each other, releasing a relatively large quantity of energy, which can be calculated using the formula e=mc2, where e is the released energy in joules, m is the mass of the particles in kilograms, and c is the speed of light in metres per second
How many grams of iron will be needed to react completely with an excess of oxygen to form 40 grams of iron3 oxide?
To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
Why do antimatter and matter react when they touch what's the chemistry of it?
Matter-Antimatter reactions are not chemical reactions. They are very complex sub-atomic reactions, and the nature of the annihilation depends on the matter and anti-matter in the reaction.One of the simplest matter-antimatter annihilations is between an electron and a positron (an anti-electron). The electron has a negative charge and the positron has a positivecharge. When they come in to contact (under the right conditions) they must annihilate, since one cancels out the other.However matter cannot simply dissappear, so it must be converted to energy via E = mc^2 where E is the energy released, m is the combined mass of the electron and positron, and c is the speed of light.In the case of the electron-positron annihilation this results in two gamma rays of a certain energy.As the size and complexity of the matter-antimatter reactions increases so does the complexity of the reactions.
How many grams of CO are needed to react with 3.16 g of Fe2O3?
To calculate the grams of CO needed to react with Fe2O3, you need to write a balanced chemical equation for the reaction, determine the moles of Fe2O3 given the mass provided, and use the stoichiometry of the balanced equation to find the moles of CO needed. Finally, convert the moles of CO to grams using the molar mass of CO.
Is antimatter a possible energy solution?
Yes and no. In order for a technology to perform well as an alternative energy solution, it has to yield much more energy than is expended in producing that form of energy. Plus, it has to be somewhat readily attainable, given our existing state of technological advancement. In the case of matter-antimatter reactions (such as proton-antiproton collisions), 100% of the matter from both matter and antimatter forms combines to convert to pure energy. So, it seems very promising as, not only an abundant source of energy, but also a clean one. However, currently, it takes a great amount of energy to create antimatter (in particle accelerators) and to try to contain it. Separating, channeling, and containing antimatter is another difficult task. As antiparticles are created, we need a means of quickly separating them from regular matter and then containing them in a "magnetic bottle" (a container that generates a magnetic field so as to trap the antimatter in a partial vacuum, so as to prevent it from escaping to react with standard matter). So, while we may discover a means of stockpiling antimatter in the future to be used as a clean, abundant energy source, we do not have that ability at the present time.
