In a 120-volt circuit, each coulomb of charge flowing receives 120 joules of energy. This is calculated using the formula: energy = voltage x charge. So, 120V x 1C = 120 joules.
119 joules per coulombCharges don't get joules as they flow through a circuit. They lose them.Every coulomb of charge that flows through a circuit ... from one terminal of a119-volt power supply, around the circuit, and back to the other terminal ...loses 119 joules during the trip.
12 watts or 12 joules of energy.In one second, 1 coulomb is 1 amp, so the power is 1 amp x 12 volts = 12 watts, and in that one second, that is 12 Joules of energy.
By definition a volt is a joule per coulomb, V=W/Q (V is voltage, W is work done or energy measured in joules, Q is charge measured in coulombs) therefore 1 volt is 1 joule per 1 coulomb of charge (1C of charge is a very large amount to expect to see very small numbers for charge)
Coulombs for charge or Joules for heat capacity
1 volt = 1 joule per coulomb 3 joules x 1 coulomb = 3 volts
119 joules per coulombCharges don't get joules as they flow through a circuit. They lose them.Every coulomb of charge that flows through a circuit ... from one terminal of a119-volt power supply, around the circuit, and back to the other terminal ...loses 119 joules during the trip.
it would be 10 joules because all you do is divide 10 joules by 1 coulomb of charge and you get 10 joules or (V) volts
12 watts or 12 joules of energy.In one second, 1 coulomb is 1 amp, so the power is 1 amp x 12 volts = 12 watts, and in that one second, that is 12 Joules of energy.
By definition a volt is a joule per coulomb, V=W/Q (V is voltage, W is work done or energy measured in joules, Q is charge measured in coulombs) therefore 1 volt is 1 joule per 1 coulomb of charge (1C of charge is a very large amount to expect to see very small numbers for charge)
Coulombs for charge or Joules for heat capacity
A joule/coulomb is represented by the volt. Example: a 9v battery provides 9 joules of energy to every coulomb of charge that passes through it.
1 volt = 1 joule per coulomb 3 joules x 1 coulomb = 3 volts
You need to multiply the number of coulombs by the number of volts. If the two batteries are in series, then you can add the voltage of both batteries.
That depends on the voltage. In general, a coulomb of charge will either gain or lose (depending on the direction) one joule of energy for every volt of potential difference. For example, if the battery has 12 V, a coulomb of charge will gain or lose 12 joules of energy when going from one terminal to the other.
<p><p> Voltage = 6 V Charge = 1 C Current * Time = Charge V * t = Q Energy = Current * Voltage * Time E = VIt E = Q * V E = 1 C * 6 V E = 6 Joules Therefore energy given to each coulomb of chare passing through 6 V battery is 6 Joules . Cheers !
Each Coulomb of charge passing through a 6V battery gains 6 Joules of energy. This can be calculated using the formula Energy = Charge x Voltage. So, for every Coulomb of charge passing through a 6V battery, it receives 6 Joules of energy.
The potential difference ('voltage') is equal to the work done per unit charge, i.e. the energy given to each Coulomb of charge. So, a six Volt battery provides six Joules of energy to each Coulomb of charge.