119 joules per coulomb
Charges don't get joules as they flow through a circuit. They lose them.
Every coulomb of charge that flows through a circuit ... from one terminal of a
119-volt power supply, around the circuit, and back to the other terminal ...
loses 119 joules during the trip.
In a 120-volt circuit, each coulomb of charge flowing receives 120 joules of energy. This is calculated using the formula: energy = voltage x charge. So, 120V x 1C = 120 joules.
The mathematical relationship between charge (q) and the Coulomb force (F) is given by Coulomb's Law, which states that the magnitude of the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this relationship is expressed as F = k(q1*q2)/r^2, where F is the Coulomb force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb constant.
<p><p> Voltage = 6 V Charge = 1 C Current * Time = Charge V * t = Q Energy = Current * Voltage * Time E = VIt E = Q * V E = 1 C * 6 V E = 6 Joules Therefore energy given to each coulomb of chare passing through 6 V battery is 6 Joules . Cheers !
By definition a volt is a joule per coulomb, V=W/Q (V is voltage, W is work done or energy measured in joules, Q is charge measured in coulombs) therefore 1 volt is 1 joule per 1 coulomb of charge (1C of charge is a very large amount to expect to see very small numbers for charge)
The magnitude formula for the electric force between two point charges is given by Coulomb's law: F = k * |q1 * q2| / r^2, where F is the electric force, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
No way of telling. to get amps you have to have a current flow, which you get when you connect a consumer to an outlet. Then the consumer will pull amps according to its wattage rating (Watts / Volts = amps) - assuming it's all hooked to a fuse with enough rating.
In a 120-volt circuit, each coulomb of charge flowing receives 120 joules of energy. This is calculated using the formula: energy = voltage x charge. So, 120V x 1C = 120 joules.
The mathematical relationship between charge (q) and the Coulomb force (F) is given by Coulomb's Law, which states that the magnitude of the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this relationship is expressed as F = k(q1*q2)/r^2, where F is the Coulomb force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb constant.
<p><p> Voltage = 6 V Charge = 1 C Current * Time = Charge V * t = Q Energy = Current * Voltage * Time E = VIt E = Q * V E = 1 C * 6 V E = 6 Joules Therefore energy given to each coulomb of chare passing through 6 V battery is 6 Joules . Cheers !
The potential difference ('voltage') is equal to the work done per unit charge, i.e. the energy given to each Coulomb of charge. So, a six Volt battery provides six Joules of energy to each Coulomb of charge.
1.5 volts means 1.5 joules/coloumb.
By definition a volt is a joule per coulomb, V=W/Q (V is voltage, W is work done or energy measured in joules, Q is charge measured in coulombs) therefore 1 volt is 1 joule per 1 coulomb of charge (1C of charge is a very large amount to expect to see very small numbers for charge)
The magnitude formula for the electric force between two point charges is given by Coulomb's law: F = k * |q1 * q2| / r^2, where F is the electric force, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
The Coulomb electric force equation is given by F = k * |q1 * q2| / r^2, where F is the force between two point charges q1 and q2 separated by a distance r, and k is the Coulomb constant.
Coulomb's law describes the electrostatic force between two charged objects. The mathematical equation is given by ( F = k \frac{|q_1 q_2|}{r^2} ), where ( F ) is the magnitude of the force between the charges, ( k ) is Coulomb's constant, ( q_1 ) and ( q_2 ) are the magnitudes of the charges, and ( r ) is the distance between the centers of the two charges. This law states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
According to Coulomb's law, the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, the force (F) is given by F = k * (q1 * q2) / r^2, where q1 and q2 are the magnitudes of the two charges, r is the distance between them, and k is the Coulomb's constant.
Electric charges are typically measured in units called coulombs (C). One coulomb is equivalent to the amount of charge flowing past a given point in one second when the current is one ampere. Instruments such as an ammeter or a coulomb meter can be used to measure electric charges.