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Molecular weight of water is 18 so 9 moles is 162 grams. Latent heat of vaporisation is 550 cal/gram, so the amount of heat is 89100 cal or 89.1 kcal.

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When water is vapourisied energy is absorbed or released?

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How many kilocalories were absorbed by the water iif you have 175g of water and it was heated from 15 degrees celsius to 88 degrees Celsius?

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175g of water was heated from 15 to 88 C How many kilocalories were absorbed by the water?

First we take 88 degrees and we subtract 15 degrees. We get 73 degrees difference. Then we multiply our 175 g of water by the temperature increase of 73 degrees. We get 12,775 calories. To get Kilocalories we must divide our calories by 1000. Why don't you do that?


175g of water was heated from 15 degrees Celsius to 88 degrees Celsius. How many kilocalories were absorbed by the water?

The specific heat capacity of water is 1 calorie/gram °C. To calculate the calories absorbed, first find the temperature change (88 - 15 = 73°C). Then, use the formula: Q = m * c * ΔT, where Q is the heat absorbed, m is the mass of water (175g), c is the specific heat capacity of water, and ΔT is the temperature change. Therefore Q = 175g * 1 cal/g°C * 73°C = 12775 calories. To convert to kilocalories, divide by 1000: 12775 calories = 12.775 kilocalories.


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