Its gravitational potential energy is (mass) x (gravity) x (height) = (5 x 9.8 x 6) = 294 joules.
That's the amount of work that gravity will do to that mass in pulling it to the ground, and
if you couple it to something else by some suitable mechanical arrangement, you can re-direct
a large part of that gravitational energy to accomplish some useful task for you.
(I say "a large part of that ... energy" rather than all of it, because no mechanical
arrangement is going to be 100% efficient, and some of the energy is going to be
lost in the levers and gears.)
Before we leave the subject, it's worth considering where that energy came from ...
how it got packed into the 5kg mass in the first place. It turns out that the 294 joules
is the work that YOU had to do, against gravity, to raise that 5kg up 6 m off the ground.
So if the task you need done involves some time flexibility, you might just as well use
your own work and energy to do the task directly and get it over with, because you're
going to lose a good bit of it in the process of lifting the 5kg and then using the fall of
the 5kg to do the task. In our real world, moving energy from one place to another,
or changing it from one form to another for storage, ALWAYS incurs some loss.
Use the formula for gravitational potential energy: GPE = mgh (i.e., mass x gravity x height). The gravity is ca. 9.8 newton/kilogram.
The amount of work done is w=mgh.
A 0.650 kg basketball is dropped out of a window that is 6.46 m above the ground. The ball is caught by a person whose hands are 1.32 m above the ground. How much work is done on the ball by its weight?
work=force(distance) work=500(20) work=10000 joules
The work done is the reduction in the potential energy of the ball at 5.50 metres to its PE at 2.05 m above ground level. This is 20.6 Newtons (to 1 dp).
None. Work is the product of (force) x (distance). If the force doesn't persist while moving through a distance, then the product is zero.
The amount of work done is w=mgh.
A 0.650 kg basketball is dropped out of a window that is 6.46 m above the ground. The ball is caught by a person whose hands are 1.32 m above the ground. How much work is done on the ball by its weight?
work=force(distance) work=500(20) work=10000 joules
mg= mass * gravity = 110 * 9.8 =1078 W=mg*height=1078*12m=12,963 J
The work done is the reduction in the potential energy of the ball at 5.50 metres to its PE at 2.05 m above ground level. This is 20.6 Newtons (to 1 dp).
Attempting to obtain step by step diagrams connecting an above ground pool to a sand filter.
You don't need any work to drop a stone!
(4 x 5) kilogram-meters = 20 joules
Work: You move a mass from A to B... the work doing this was defined by multiplying the force you used with the distance A to B. Energy: i.e. the potential energy is defined by the gravity acceleration (g) multiplied with the mass (m) multiplied with the relative distance (h, usually from the ground) -> m*g*h. Now h is similar to a distance from a certain A to a certain B; force was defined by the multiplication of the mass and the acceleration the mass has... F (force) = m (mass)*a (acceleration), or in this case F = m*g. Now it can be seen: energy of a mass on altitude h above the ground: m*g*h = F*h = the work needed to lift the mass to this altitude... and as it is similar, the use of the same unit is logical. Vic because you move the mass
a structure that is above ground in which a person/ people may live in work in
Yes it will
YES it should be no problem