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Which requires more work lifting a 50 kg sack a vertical distanceof 2 m or lifting a 25kg sack a vertical distance of 4?
Lifting a 50 kg sack a vertical distance of 2 m requires more work, as work is calculated as force multiplied by distance. In this case, the weight of the sack (force) is higher, resulting in more work done compared to lifting a 25 kg sack a vertical distance of 4 m.
How much work is done in lifting a 60Kg crate a vertical distance of 10 meters?
The work done in lifting a 60kg crate a vertical distance of 10 meters is given by the formula: work = force x distance x cos(theta), where force = weight x gravitational acceleration = 60kg x 9.8 m/s^2, distance = 10m, theta is the angle between the force and direction of displacement (which is 0 in this case, as it's lifting vertically). Plugging in the values, the work done is approximately 5,880 Joules.
How much work is done when a 195g tomato is lifted 19.4m?
The work done lifting the tomato against gravity is calculated as the product of its weight (force due to gravity) and the vertical distance it is lifted. The weight of the tomato is 195g * 9.81 m/s² = 1.91 N. Therefore, the work done lifting the tomato is 1.91 N * 19.4 m = 37.03 Joules.
Explain why only the vertical height of the stairs is measured for work?
Only the vertical height of the stairs is measured for work because it accounts for the change in potential energy associated with lifting oneself to a higher elevation against gravity. The horizontal distance does not significantly affect the amount of work done as it does not require overcoming any vertical displacement.
What is the amount of work done lifting a 250 N box up a distance of 1.5 M?
The work done in lifting a 250 N box up a distance of 1.5 m is 375 Joules. This is calculated by multiplying the force (250 N) by the distance (1.5 m) over which the force is applied.
Which requires more work lifting a 50 kg sack a vertical distanceof 2 m or lifting a 25kg sack a vertical distance of 4?
Lifting a 50 kg sack a vertical distance of 2 m requires more work, as work is calculated as force multiplied by distance. In this case, the weight of the sack (force) is higher, resulting in more work done compared to lifting a 25 kg sack a vertical distance of 4 m.
How much work is done in lifting a 60Kg crate a vertical distance of 10 meters?
The work done in lifting a 60kg crate a vertical distance of 10 meters is given by the formula: work = force x distance x cos(theta), where force = weight x gravitational acceleration = 60kg x 9.8 m/s^2, distance = 10m, theta is the angle between the force and direction of displacement (which is 0 in this case, as it's lifting vertically). Plugging in the values, the work done is approximately 5,880 Joules.
How much work is done when a 195g tomato is lifted 19.4m?
The work done lifting the tomato against gravity is calculated as the product of its weight (force due to gravity) and the vertical distance it is lifted. The weight of the tomato is 195g * 9.81 m/s² = 1.91 N. Therefore, the work done lifting the tomato is 1.91 N * 19.4 m = 37.03 Joules.
Why does a ramp not reduce the amount of work. Please explain in words or with numbers?
Assuming 100% efficiency, the amount of work depends on the weight and the vertical distance (that is, opposite to the pull of gravity) moved. If you use a ramp then you reduce the force by an amount k, that's true, but the distance you have to push in the direction of the force is multiplied by k. The work done is [original force]/k times [vertical distance]times k and the k cancels out. For vertical lifting k=1.
Explain why only the vertical height of the stairs is measured for work?
Only the vertical height of the stairs is measured for work because it accounts for the change in potential energy associated with lifting oneself to a higher elevation against gravity. The horizontal distance does not significantly affect the amount of work done as it does not require overcoming any vertical displacement.
What is the amount of work done lifting a 250 N box up a distance of 1.5 M?
The work done in lifting a 250 N box up a distance of 1.5 m is 375 Joules. This is calculated by multiplying the force (250 N) by the distance (1.5 m) over which the force is applied.
Would you do more work lifting a box from the floor to the top of a table or from the floor to a shelf above your head?
Work is done by a force acting on a mass when that mass is displaced (moved).Basically, more work is required to move a mass through a greater distance, similarly more work is required to move a greater mass though the same distance.Providing all other things are equal, if the same box is moved through a distance of two metres you do more work than moving the box through one metre.
How much work you need to move a 280n shed to a platform 5 m above?
The work needed to move the shed to a platform 5m above would depend on the distance it needs to be moved horizontally and the method of moving it. The work done in lifting the shed against gravity can be calculated using the formula: work = force x distance x cos(angle), where the force is the weight of the shed (280 N), the distance is the vertical height (5m), and the angle is the angle between the force and the direction of movement (typically 0 degrees for vertical lifting).
How much work is done when a 1-kg mass is raised a vertical distance of 1 m?
The work done is equal to the force needed to lift the mass multiplied by the vertical distance lifted. In this case, the work done is equal to the gravitational force acting on the mass (m x g) multiplied by the vertical distance lifted (1 m). So, the work done would be 1 kg * 9.8 m/s^2 * 1 m = 9.8 Joules.
Does changing the distance of a ramp in an inclined plane affect the amount of work being done?
No, changing the distance of a ramp in an inclined plane does not affect the amount of work being done. Work done on an object on an inclined plane is only dependent on the vertical height through which the object is lifted, not the distance along the inclined plane. Work done is calculated as the force applied multiplied by the vertical height.
How much work is done when a 700 N refrigerator is lifted straight up a distance of 4 meters in joules?
The work done in lifting the refrigerator can be calculated by multiplying the force applied (700 N) by the distance traveled (4 meters). Therefore, the work done would be 700 N * 4 meters = 2800 joules.
How much work is done in lifting a 50kg object to height of 5m?
The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).
