The work done in lifting a 60kg crate a vertical distance of 10 meters is given by the formula: work = force x distance x cos(theta), where force = weight x gravitational acceleration = 60kg x 9.8 m/s^2, distance = 10m, theta is the angle between the force and direction of displacement (which is 0 in this case, as it's lifting vertically). Plugging in the values, the work done is approximately 5,880 Joules.
The work done by a crane lifting a 240 kg crate to a height of 165 meters is equal to the change in potential energy of the crate. The work done can be calculated using the formula: Work = force x distance. In this case, the force is equal to the weight of the crate (240 kg x 9.8 m/s^2) and the distance is 165 meters.
We have no way of knowing what power the machine was rated for, but with the information given in the question, we can calculate the power it delivered during the crate-lift: It was (1.96) x (mass of the crate in kilograms) x (distance the crate was lifted in meters) watts.
yes
The work done is given by the formula Work = Force x Distance. Rearranging this formula we find Distance = Work / Force. Plugging in the values given, we get Distance = 68 joules / 4 newtons = 17 meters. So, the crate was moved 17 meters.
The work done on the crate would be 40 joules (work = force x distance).
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
The work done by a crane lifting a 240 kg crate to a height of 165 meters is equal to the change in potential energy of the crate. The work done can be calculated using the formula: Work = force x distance. In this case, the force is equal to the weight of the crate (240 kg x 9.8 m/s^2) and the distance is 165 meters.
We have no way of knowing what power the machine was rated for, but with the information given in the question, we can calculate the power it delivered during the crate-lift: It was (1.96) x (mass of the crate in kilograms) x (distance the crate was lifted in meters) watts.
yes
The work done is given by the formula Work = Force x Distance. Rearranging this formula we find Distance = Work / Force. Plugging in the values given, we get Distance = 68 joules / 4 newtons = 17 meters. So, the crate was moved 17 meters.
The work done on the crate would be 40 joules (work = force x distance).
The work done in lifting the crate is equal to its change in potential energy: ( \text{Work} = \text{Force} \times \text{distance} = m \cdot g \cdot h ). The power required is the work done divided by the time taken: ( \text{Power} = \frac{\text{Work}}{\text{time}} ). Plug in the values to calculate the power required.
Work = force x distance = Newtons x meters = 1937 Joules.
The work done is calculated as the force applied multiplied by the distance traveled in the direction of the force. In this case, the work done is 75 Joules (15 N * 5 m) when pushing the 25 kg crate with a force of 15 Newtons over a distance of 5 meters.
Potential Energy is given by the fourmulai PE=MGH where M=mass in kilos, G=the force of gravity in Netwons (9.8N) and H=height in meters. So 50*9.8*10=4900joules. A Watt is a unit of power that =1 joule per second. So 4900 joules divided by 5 seconds = 980 Watts, not allowing for losses due to friction etc.
You don't actually lift the crate. You drag it. To do so you touch the crate with your stylus and without lifting the stylus drag your Jonas to the spot you want to take the crate to and release.
The work done can be determined by dividing the work by the force applied. Therefore, the distance the crate will be moved is 4 meters (2800 J / 700 N).