The work done on the crate would be 40 joules (work = force x distance).
The work done by a crane lifting a 240 kg crate to a height of 165 meters is equal to the change in potential energy of the crate. The work done can be calculated using the formula: Work = force x distance. In this case, the force is equal to the weight of the crate (240 kg x 9.8 m/s^2) and the distance is 165 meters.
Work = force x distance = Newtons x meters = 1937 Joules.
From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
The work done on the crate would be 4000 joules (W = F x d), as work is the product of force (200 N) and distance (20 m).
The work done to lift the object is equal to the force applied multiplied by the distance moved in the direction of the force. In this case, the work done would be 500 newtons x 8 meters = 4000 joules.
The work done by a crane lifting a 240 kg crate to a height of 165 meters is equal to the change in potential energy of the crate. The work done can be calculated using the formula: Work = force x distance. In this case, the force is equal to the weight of the crate (240 kg x 9.8 m/s^2) and the distance is 165 meters.
80 J
Work = force x distance = Newtons x meters = 1937 Joules.
From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
C.50 j
The work done on the crate would be 4000 joules (W = F x d), as work is the product of force (200 N) and distance (20 m).
The work done to lift the object is equal to the force applied multiplied by the distance moved in the direction of the force. In this case, the work done would be 500 newtons x 8 meters = 4000 joules.
The work done is calculated as the force applied multiplied by the distance traveled in the direction of the force. In this case, the work done is 75 Joules (15 N * 5 m) when pushing the 25 kg crate with a force of 15 Newtons over a distance of 5 meters.
The work done by a crane to lift a 1 kg car 10 meters would be 98.1 Joules. This is calculated as the product of the force required to lift the car (9.81 N/kg) and the distance the car is lifted (10 meters).
The work done to lift the petrified log 5 meters can be calculated using the formula: work = force × distance. In this case, the work required would be 25,000 joules (5000 N × 5 meters).
To calculate the work done when lifting an object, you can use the formula: work = force × distance. The force required to lift an object is equal to its weight, which is mass × gravity. So, you would need to know the mass of the object to calculate the work done when lifting it 1600 meters.
Work done is equal to force multiplied by distance in the direction of the force. In this case, work done on the car is 12000 N * 2 m = 24000 J.