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How much work is done when a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5m?
Wiki User
∙ 13y ago
Work = (force) x (distance)
IF the force is parallel to the floor, i.e. horizontal, then the force acts through 1.5 m.
Work = (800) x (1.5) = 1,200 newton-meters = 1,200 joules.
Wiki User
∙ 13y ago
Wiki User
∙ 12y agoFirst of all, since you're 'raising' the crate, it looks like it doesn't matter what kind of
floor is under it.
Work = (force) x (distance)
If the entire 800.0N is appllied to raising the crate, then Work = (800) x (1.5) = 1,200 joules.
Coincidentally, this is exactly the amount of potential energy that the crate gains
from being lifted 1.5 meter higher !
Wiki User
∙ 14y agow=f*deltax*cosQ
for this question you know w=1200 and deltax=1.5 and since it is on the floor cosQ is 1
then
1200=f*1.5*1
then you can find the f
Wiki User
∙ 10y agoPlease use the definition of work, as force x distance. This assumes that the force pushes in the same direction as the movement, and that the force is constant.
Wiki User
∙ 13y ago800N x 1.5m = 1200 J
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How much work is done whet a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 m?
W = Fd = 800 x 1.5 = 1200
How much work in joules is performed when a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 meters?
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
friction
When a person pushes a crate across the floor what is the effect?
It goes across.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
Friction force = -F The crate is at rest, so all forces must be balanced
How much work is done whet a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 m?
W = Fd = 800 x 1.5 = 1200
How much work in joules is performed when a force of 800.0 N is exerted while pushing a crate across a level floor for a distance of 1.5 meters?
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
friction
How do you get the three cubes to get the button in snowpeak in Zelda twilight princess?
The first time you enter the room. Start by pushing the crate in the southeast corner across to the southwest. Then push the crate in the northwest corner across the room so it toches the iced crate. Stand behind the crate you just pushed and push it to the south. Then push the same crate westone space so it hits the first crate. Now push the crate one more time south and the switch will be activated. The second time you need to enter the room is different. start by pushing the crate to the north south. Go to the south and shove the crate to the middle of the puzzle so it passes over the middle floor switch. Now shove the crate that's on the eastern edge west then north. So Its sitting in front of the middle floor switch. Run to the crate that's furthest north and push it clockwise around the rim of the puzzle so it hits the crete you have yet to move. Finally face north and push the crate so it is on the switch leading upstairs.
When a person pushes a crate across the floor what is the effect?
It goes across.
If a crate accelerates at 2.5 m5 and if the net force exerted is about 500N what is the mass of the crate?
In accordance to Newton's Second Law, you need to divide the force by the acceleration. The answer in this case will be in kilograms.
If you push on a heavy crate to the right and it slides what is the direction of friction on the crate?
The direction of friction on the crate is opposite to the direction in which it is sliding. In this case, since you are pushing the crate to the right, the friction will act to the left in order to oppose the motion.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
Friction force = -F The crate is at rest, so all forces must be balanced
What is the friction force if a crate is at rest on the surface and a horizontal force of 50N is applied to it?
For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.
A man pushes a crate along a factory floor by exerting a force if 55n if the crate moves a distance of 4.0m how much work does the man perform?
Work = force x distance Work = 55 x 4 = 220J
A 1500 N crate is being pushed across a level floor at a constant speed. What will be the acceleration of the crate?
0 since the speed is constant
How much work did the movers do horizontally pushing a 150 kg crate 10.4 m across a rough floor without acceleration if the effective coefficient of friction was 0.70?
10920 joules if the accelaration due to gravity is taken to be 10m/s/s
