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How would you estimate the maximum height you could throw a ball vertically upward?
Anyone who is trying to figure out how high they can vertically throw an object like a ball has a little math to do. The calculation needed is the time it takes the ball to reach its max height multiplied by the rate at which gravity kicks in. Take that number and divide it in half.
What else can I help you with?
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
When a buulet is fired upward verticallyit gains in?
When a bullet is fired upward vertically, it gains potential energy due to the increase in its height above the ground. As the bullet rises, its kinetic energy decreases and is converted into potential energy until it reaches its maximum height.
What is the boy throw a stone vertically upward with an initial velocity of 6.0 ms?
The boy throws a stone vertically upward with an initial velocity of 6.0 m/s, meaning the stone is moving against gravity. It will reach a maximum height and then fall back down due to gravity. The stone will eventually return to the ground after reaching its highest point.
A particle is projected vertically upward and it reaches the maximum height H in time T seconds the height of the particle at any time t will be?
The height of the particle at any time t can be represented by the equation h(t) = H - (1/2)gt^2, where H is the maximum height reached, g is the acceleration due to gravity, and t is the time. At time T, the height of the particle is H, and the height decreases as time increases beyond T due to gravity acting on the particle.
Why does the speed dcreses when an object is thrown vertically up?
The speed decreases when an object is thrown vertically up because of the force of gravity acting against the object's upward motion. As the object goes higher, the force of gravity slows it down until the object reaches its maximum height, where its speed momentarily becomes zero before accelerating back downward.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
When a buulet is fired upward verticallyit gains in?
When a bullet is fired upward vertically, it gains potential energy due to the increase in its height above the ground. As the bullet rises, its kinetic energy decreases and is converted into potential energy until it reaches its maximum height.
What is the boy throw a stone vertically upward with an initial velocity of 6.0 ms?
The boy throws a stone vertically upward with an initial velocity of 6.0 m/s, meaning the stone is moving against gravity. It will reach a maximum height and then fall back down due to gravity. The stone will eventually return to the ground after reaching its highest point.
A particle is projected vertically upward and it reaches the maximum height H in time T seconds the height of the particle at any time t will be?
The height of the particle at any time t can be represented by the equation h(t) = H - (1/2)gt^2, where H is the maximum height reached, g is the acceleration due to gravity, and t is the time. At time T, the height of the particle is H, and the height decreases as time increases beyond T due to gravity acting on the particle.
Why does the speed dcreses when an object is thrown vertically up?
The speed decreases when an object is thrown vertically up because of the force of gravity acting against the object's upward motion. As the object goes higher, the force of gravity slows it down until the object reaches its maximum height, where its speed momentarily becomes zero before accelerating back downward.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
What does vertically upwards mean?
Vertical means straight up and down,aligned with the direction of gravity. Vertically upward means vertical in the up direction. So if you jump directly straight up that is vertically upward; when you land you are travelling vertically downward.
How does earth move vertically upward?
because if gravity
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
1 If you toss a ball upward with a certain velocity it falls freely and reaches a maximum height h What maximum height does the ball reach if you throw it upward with double the initial velocity?
Multiply the height by 4. The equation to use is h=-16t2 + v0t + h0. Use whatever values you want for v0 and h0, and find the vertex of the parabola. Then double your value of v0, and find the vertex of your new parabola. It will be 4 times as high every time. By the way, to find the vertex, plug in v0/32 for t. Then solve for h.
An object is thrown vertically upward when does it reach maximum height?
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
A rocket is launched upward with a velocity of 64 feet per second from the top of a 95-foot structure What is the maximum height attainrd by the rocket?
The rocket would attain a maximum height of 158.65 feet (63.65 feet from the top of the structure).
