0
What else can I help you with?
A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity during this 5 second interval her acceleration?
is constantly decreasing until it reaches zero when she reaches terminal velocity. At that point, her acceleration is zero and she falls at a constant speed, experiencing air resistance equal in magnitude to her weight.
A 75kg person and 200kg crate are each parachuted tto earth from a plane which statement is true?
Both the person and the crate experience the same acceleration due to gravity, regardless of their masses, when they are in free fall under the parachute. However, the person will experience a greater air resistance due to their larger surface area compared to the crate, causing them to slow down more quickly and have a lower terminal velocity.
If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?
If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.
How does the path of the crate appear to somebody on the airplane and to someone on the ground when a crate is dropped from an airplane flying horizontally at constant speed?
To someone on the airplane, the crate would appear to fall straight down due to its initial horizontal velocity matching the airplane's speed. To someone on the ground, the crate would follow a parabolic path because of gravity acting on it vertically while it moves horizontally due to its initial velocity.
If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?
If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.
A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity during this 5 second interval her acceleration?
is constantly decreasing until it reaches zero when she reaches terminal velocity. At that point, her acceleration is zero and she falls at a constant speed, experiencing air resistance equal in magnitude to her weight.
A 75kg person and 200kg crate are each parachuted tto earth from a plane which statement is true?
Both the person and the crate experience the same acceleration due to gravity, regardless of their masses, when they are in free fall under the parachute. However, the person will experience a greater air resistance due to their larger surface area compared to the crate, causing them to slow down more quickly and have a lower terminal velocity.
If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?
If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.
How does the path of the crate appear to somebody on the airplane and to someone on the ground when a crate is dropped from an airplane flying horizontally at constant speed?
To someone on the airplane, the crate would appear to fall straight down due to its initial horizontal velocity matching the airplane's speed. To someone on the ground, the crate would follow a parabolic path because of gravity acting on it vertically while it moves horizontally due to its initial velocity.
If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?
If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.
You are pushing a kg wooden crate across the floor. the force of sliding friction on the crate is 90 N. how much force must you exert on the crate to keep it moving with a constant velocity?
To keep the crate moving with constant velocity, the force you exert must balance the force of sliding friction. In this case, you must exert a force of 90 N in the opposite direction of the sliding friction, so the net force on the crate is zero and it remains in motion at a constant velocity.
What is the net force acting on a sliding crate?
The net force on a sliding crate is the vector sum of all forces acting on the crate. It is the force that is causing the crate to accelerate or decelerate. If all forces are balanced, the net force will be zero and the crate will move at a constant velocity.
When a crate slide down an incline at a constant velocity it is?
When a crate slides down an incline at a constant velocity, it is experiencing a balanced force situation. The force of gravity pulling it downhill is counteracted by the force of friction acting in the opposite direction. This results in the crate moving steadily without speeding up or slowing down.
When a person pushes a crate across the floor what is the effect?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
What force is needed to slide a 250-kg crate across the floor at constant velocity if the coefficient of sliding friction between a crate and a horizontal floor is 0.25?
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
If a crate weighing 508 N is resting on a plane inclined 26degrees above the horizontal if acceleration is 4.29 then how fast will the crate be moving after 6 seconds?
To determine the speed of the crate after 6 seconds, we first need to calculate the net force acting on the crate on the inclined plane. This can be done by resolving the weight of the crate into components parallel and perpendicular to the plane. Then, using Newton's second law, F = ma, where F is the net force, m is the mass of the crate, and a is the acceleration, we can find the acceleration down the incline. After finding this acceleration, we can use the kinematic equation v = u + at to calculate the final speed of the crate after 6 seconds, where v is the final velocity, u is the initial velocity (assumed to be 0), a is the acceleration, and t is the time.
