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It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
It takes 1 kcal to raise the temperature of 1 kg of water by 1 degree C. To do this accurately, you need the temperature of the water to determine its density, but for the sake of simplicity, we'll use its value at 4oC, which is 1 g/ml 373 ml is equal to 373g or 0.373kg. Therefore, for that volume of water it should take 0.373 kcal per degree C., so 0.373 x 30 = 11.19 kcal, or 11,190 cal
Yes, water has a definite volume. It takes up a specific amount of space, which is why you can measure it in liters or milliliters. The volume of water can change depending on its temperature and pressure, but it will always have a definite volume at any given time.
To calculate the total number of calories of heat needed, you can use the formula: Q = m * c * ΔT, where Q is the heat energy in calories, m is the mass of the water, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the change in temperature. Assuming you have 100 grams of water, the calculation would be: Q = 100g * 1 cal/g°C * 10°C = 1000 calories.
No. Temperature is measured in degrees celsius. Thermal energy, which causes temperature change, is measured in calories or british thermal units. A calorie, not a food calorie, is the amount of heat necessary to raise 1 ml of water 1 degree celsius. 252 calories = 1 btu. 1 food calorie is actually equivalent to 1000 calories of heat.
For one gram of ice, it takes 11.9 calories to change the temperature to 0°, 80 calories to melt the ice, 100 calories to raise the water temperature to 100°, 540 calories to change the water to steam, and 23 calories to raise the steam temperature to 123°. That's a total of (11.9 + 80 + 100 + 540 + 23) calories or 754.9 calories. So to do the same to 55.6 grams of ice requires 55.6 times as much heat. 754.9 calories times 55.6 equals approximately 41972 calories (about 42 kilocalories).
Water has no calories no matter what the temperature is
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
The water releases 42 joules.The formula for heat is: q = mCT.The temperature of the water decreases by 1°C. The number of calories required for this change is the product of the mass of the substance, its specific heat, and the temperature change: 10 g × 1°C × 4.2 J/°C. g = 42 joules.
To change a liquid into solid at constant temperature, an amount of heat is released equal to the latent heat of that liquid. For water it is about 80 calories per gram.
It depends on what temperature is is at and how much water there is.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
The teamperature does not change
The answer is actually partially dependent on the starting temperature of the water (heat capacity is a function of temperature). You will still be close enough for most purposes if you assume that it takes 1 calorie to heat 1 gram of water 1 °C. With this assumption it takes 1000 calories to heat 1 kg of water °C and 5000 calories to heat 1 kg of water 5 °C. 5000 cal = 5 kilocalories = 20929 joules.
When a physical change takes place, a certain element or chemical will change its shape and in many cases, the volume too. Water takes the shape of the mold casing once it freezes.
To calculate the calories absorbed by the water bath, we can use the formula: Q = mcΔT, where Q is the heat absorbed (in calories), m is the mass of water (100 g), c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the temperature change (5 °C). Plugging in the values, we get Q = 100g * 1 cal/g °C * 5 °C = 500 calories. Thus, the water bath absorbs 500 calories.