If it has constant temperature (one can do this by dipping it in a beaker of water) it can be considered an ohmic conductor since Ohm's law states that the Voltage and amperage are directly proportional in a metallic conductor of constant temperature.
3.0 or threeAnswerIt depends how they are connected.In series, ther total resistance will be 220 ohms and, so, the current will be 120/220 = 0.545 A.In parallel, ther total resistance will be 20 ohms and, so, the current will be 120/20 = 6 A.
I = E/R = 20/10 = 2 Amperes.Note: Don't try this at home.The power dissipated by a resistor is I2R = 40 watts for this one.Unless your 10-ohm resistor is actually the coil in a toaster, a resistorthat's not effectively heat-sunk and is trying to dissipate 40 watts willdefinitely get very hot, and could even shatter, spraying little bits ofhot carbon dust all over the place.Be careful.
Here are some practice questions based on Ohm's Law: If a resistor has a resistance of 10 ohms and a current of 2 amperes flowing through it, what is the voltage across the resistor? A circuit has a voltage of 12 volts applied across a resistor with a resistance of 4 ohms. What is the current flowing through the resistor? If a circuit has a current of 0.5 amperes flowing through a resistor with a resistance of 8 ohms, what is the voltage across the resistor? These questions will help you practice applying Ohm's Law to calculate voltage, current, and resistance in electrical circuits.
The current flowing through the resistor can be calculated using Ohm's Law, which states: Current (I) = Voltage (V) / Resistance (R). Plugging in the values given, the current would be 12 amps.
If you're sure that every resistor is exactly 10 ohms, and you need exactly13.75 ohms, then you can do it this way:-- Connect four resistors in parallel. Effective resistance of the combination = 2.5 ohms.-- Connect eight resistors in parallel. Effective resistance of the combination = 1.25 ohms.-- Connect in series: the 4-resistor unit, the 8-resistor unit, and a single 10-ohm resistor.Effective resistance of the combination = (2.5 + 1.25 + 10) = 13.75 ohms.In the real world, however, the combination of (2.5 + 10) = 12.5 would be closeenough to work. And actually, a single 10-ohm resistor might be close enough.Or you could just connect a single 10-ohm resistor to the ohm-meter, take afingernail file, file a small notch in the side of the resistor while watching themeter, stop filing when the resistance arrives at 13.4 ohms, see what it is whenit cools from all the filing and settles down, then make small additional scrapesuntil you have your 13.75 ohms. This might be just as fast as the 23 solder-joints required for the procedure described above, and you save 12 resistors !So what could be bad ! ?
The current would be about 20 volts.
3
2
Rt = 10
No, a 2.2k ohm resistor and a 220 ohm resistor are not the same resistance. The "k" in 2.2k ohm stands for "kilo," which represents a multiplier of 1000. Therefore, a 2.2k ohm resistor is equivalent to 2200 ohms, while a 220 ohm resistor is simply 220 ohms. The difference in resistance values is a factor of 10 due to the kilo prefix.
10 Ohms.
The 5 Ohm resistor will have more current passing through it than the 10 ohm resistor. Since the resistors are in parallel the Voltage across each resistor is the same. Power or the amount of heat in terms of the question can be derived from Power = Voltage * Current. Ohm's law tells us that the current flowing through a resistor is equal to the Voltage across the resistor divided by the resistance. The formula for power is then the Voltage * Voltage / Resistance. Since V^2 / 10 is smaller than V^2 / 5 we know that the 5 ohm resistor will always have more power dissipated than the 10 ohm resistor.
100 megohm the 10 ohms completely vanishes in the tolerance of the 100 megohm resistor, in that range tolerances can exceed 20% of nominal.
There will be 20 amps flowing through the 5 ohm resistor. We could do some math and all to figure voltage drops and some other things, but let's cut to the chase and see what's happening. Based on what we know about series circuits and about parallel circuits, we can shred this in nothing flat. So let's. First, we're told 30 amps flows in the circuit. That's the total current, and it will be the current through the first 10 ohm resistor. It has to be. The the 30 amps "splits" to flow through the parallel network of the 10 ohm and 5 ohm resistors. That's 30 amps that has to "split" and some will go through the 10 ohm resistor and some will go through the 5 ohm resistor. With me? Sure. Now for the "trick" here. Since the 5 ohm resistor has only half the resistance of the 10 ohm resistor, twice as much current will flow through it as the 10 ohm resistor. Make sense? Yup. Let's finish this. Since there is twice as much current flowing in the 5 ohm resistor 'cause it's got half the resistance of the 10 ohm resistor, if we have "x" amount of current flowing in the 10 ohm resistor, then we'll have "2x" amps of current flowing in the 5 ohm resistor. That's "3x" amps total, and the "3x" amps equals 30 amps. See through it now? There will be 10 amps flowing through the 10 ohm resistor, and 20 amps flowing through the 5 ohm resistor. Piece of cake.
The resistors are 5, 10, and 15 ohms.The current through the 5-ohm resistor is E/R = 15/5 = 3 Amp.The current through the 10-ohm resistor is E/R = 15/10 = 1.5 Amp.The current through the 15-ohm resistor is E/R = 15/15 = 1 Amp.Their total effective resistance in parallel is the reciprocal of [ (1/5) + (1/10) + (1/15) ] =the reciprocal of [ (6/30) + (3/30) + (2/30) ] = the reciprocal of [ (11/30) ] = 30/11 ohms .The total current drawn from the battery is E/R = (15)/(30/11) = (15 x 11/30) = 11/2 = 5.5 Amp.Note:The 5-ohm resistor is dissipating 45 watts.The 10-ohm resistor is dissipating 22.5 watts.The 15-ohm resistor is dissipating 15 watts.The poor battery is delivering 82.5 watts.None of this is going to last very long at all.Most likely, the battery has already expired,and/or the 5-ohm resistor has already exploded,while we've been here playing with our calculators.
The voltage supplying the circuit will be divided across the series resistors in proportion to their resistance. The wattage of the resistors has no effect on the distribution, but if you put an under rated resistor in the circuit, it will fail. For example, if you have a 10v source, and a 1 ohm resistor in series with a 3 ohm resistor, the 1 ohm resistor, being only a quarter of the total resistance, will see a quarter of the voltage, or 2.5 volts. The other 7.5 volts will seen across the 3 ohm resistor. The total power consumed by the circuit is given by P = VI or V2/R or I2R, so for this circuit, the resistors will consume 25 watts (current is 10/4 = 2.5 amps according to Ohms Law), and 10 x 12.5 gives 25 watts. Hope that helps ItAintMe
V = 6 V R = 10 Ohm I = V/R = 0.6 A