That is correct. Earth's gravity, often expressed as 9.8 meters per second square, can also be expressed as the equivalent 9.8 Newton per meter. That is, an object of twice the mass will feel twice the force of attraction from Earth. However, it will also have twice the inertia - it requires twice the force to give it a certain acceleration.
That is correct. Earth's gravity, often expressed as 9.8 meters per second square, can also be expressed as the equivalent 9.8 Newton per meter. That is, an object of twice the mass will feel twice the force of attraction from Earth. However, it will also have twice the inertia - it requires twice the force to give it a certain acceleration.
That is correct. Earth's gravity, often expressed as 9.8 meters per second square, can also be expressed as the equivalent 9.8 Newton per meter. That is, an object of twice the mass will feel twice the force of attraction from Earth. However, it will also have twice the inertia - it requires twice the force to give it a certain acceleration.
That is correct. Earth's gravity, often expressed as 9.8 meters per second square, can also be expressed as the equivalent 9.8 Newton per meter. That is, an object of twice the mass will feel twice the force of attraction from Earth. However, it will also have twice the inertia - it requires twice the force to give it a certain acceleration.
That is correct. Earth's gravity, often expressed as 9.8 meters per second square, can also be expressed as the equivalent 9.8 Newton per meter. That is, an object of twice the mass will feel twice the force of attraction from Earth. However, it will also have twice the inertia - it requires twice the force to give it a certain acceleration.
True
Acceleration of a falling object is directly proportional tothe force of gravity in the object's location.
If you are asking the rate of acceleration on a surface, than the larger the force of gravity is, the more it will affect the rate of acceleration. The amount of friction depends one many variables, one of which is gravity. The larger your force of gravity is, the larger the force of friction is. Because of this, the more the force of gravity is, than the slower the rate of acceleration is because of the larger force of friction, which would be acting against the rate of acceleration. Therefore, the force of gravity does affect the rate of acceleration.
True. Assuming you can ignore air resistance, the acceleration for any object is approximately 9.8 meters per second squared.
Gravity impacts weight because weight is calculated using F = M * A. F - Weight in this case M - Mass of your object A - Acceleration of gravity on the planet the object is on. Assuming mass remains constant and your acceleration (your gravity) increases, weight will increase. If acceleration (your gravity) decreases, weight will decrease.
no
It makes things weigh more or less, depending on the surface gravity.
If you are asking the rate of acceleration on a surface, than the larger the force of gravity is, the more it will affect the rate of acceleration. The amount of friction depends one many variables, one of which is gravity. The larger your force of gravity is, the larger the force of friction is. Because of this, the more the force of gravity is, than the slower the rate of acceleration is because of the larger force of friction, which would be acting against the rate of acceleration. Therefore, the force of gravity does affect the rate of acceleration.
Acceleration does not effect gravity. It is rather the other way round. Gravity can affect the rate of acceleration.
Gravity is pretty constant figure anywhere on earth, essentially its dependent on your distance from the center of gravity of the earth, nominally it will produce an acceleration of 9.81((m/s/)/s) at the earths surface. Gravity is dependent on mass and independent of motion , ie mass of earth attracting mass of person , attraction being proportional to total mass of both and distance between their centers of gravity. However , a very small opposing acceleration outwards is experienced because you are rotating about the earths axis (centrifugal action) , its maximum effect is on the equator and zero effect at the poles. this acceleration can be calculated from: a = (v^2)/r where: a = acceleration ((m/s)/s) v = velocity (m/s) r = radius or normal distance from earths axis (m)
yes it does but the gravity is 38% of the earths gravity and if doesn't affect objects then it will have no moon
Acceleration of a falling object is directly proportional tothe force of gravity in the object's location.
Does mars' gravity affect other objects. yes it does but the gravity is 38% of the earths gravity and if doesn't affect objects then it will have no moon.
The (centripital) force due to rotation is at its greatest at the equator, if you weigh 100 kg, the force of gravity on you = approx. 982 n anywhere on earths surface, the centripetal force at the equator = 3.4 n
If you are asking the rate of acceleration on a surface, than the larger the force of gravity is, the more it will affect the rate of acceleration. The amount of friction depends one many variables, one of which is gravity. The larger your force of gravity is, the larger the force of friction is. Because of this, the more the force of gravity is, than the slower the rate of acceleration is because of the larger force of friction, which would be acting against the rate of acceleration. Therefore, the force of gravity does affect the rate of acceleration.
No. Space is literally nothing. No oxygen, no air, no dust, nothing. objects in space, yes, the earths gravity does affect it. otherwise the moon would just fly away.
True. Assuming you can ignore air resistance, the acceleration for any object is approximately 9.8 meters per second squared.
Gravity impacts weight because weight is calculated using F = M * A. F - Weight in this case M - Mass of your object A - Acceleration of gravity on the planet the object is on. Assuming mass remains constant and your acceleration (your gravity) increases, weight will increase. If acceleration (your gravity) decreases, weight will decrease.