The specific heat capacity of iron is 0.45 J/g°C. This can be calculated using the formula: Energy = mass x specific heat capacity x temperature change. Solving for specific heat capacity: 89.5 J = 5.10g x 0.45 J/g°C x (75°C-36°C).
An example of a substance with low specific heat is metal, such as iron or aluminum. These materials heat up quickly when exposed to heat and cool down quickly as well, due to their low specific heat capacity.
Water has a greater specific heat capacity.
Yes, the specific heat capacity of iron can be considered a dependent variable in a scientific experiment, as it is a characteristic that can be influenced or affected by changes in other variables being tested.
The heat absorbed by a material can be calculated using the formula Q = mcΔT, where Q is the heat absorbed, m is the mass of the material, c is the specific heat capacity of the material, and ΔT is the change in temperature. For iron, the specific heat capacity is about 0.45 J/g°C. Calculate the heat absorbed: Q = 75g * 0.45 J/g°C * (301K - 295K) = 135 Joules. Therefore, 75g of iron would absorb 135 Joules of energy as heat when heated from 295K to 301K.
No, aluminum has a lower specific heat capacity than iron. The specific heat capacity of aluminum is about 0.90 J/g°C, while iron has a specific heat capacity of about 0.45 J/g°C.
Iron has the lowest specific heat, so it will heat up faster.
There are three metals that have this specific heat cast iron, chromium and iron. You have to check the physical characteristics of the metal you used in your lab to determine which out of the three is the correct one.
Where are you getting this specific heat number. With the other numbers there is no cancellation.
Here are a couple of specific heat sample problems for practice: Calculate the amount of heat required to raise the temperature of 50 grams of water from 20C to 40C. The specific heat capacity of water is 4.18 J/gC. A 25 gram piece of iron is heated from 25C to 100C. Calculate the amount of heat absorbed by the iron. The specific heat capacity of iron is 0.45 J/gC. These problems can help you practice applying the concept of specific heat in calculations.
The specific heat capacity of iron is 0.45 J/g°C. This can be calculated using the formula: Energy = mass x specific heat capacity x temperature change. Solving for specific heat capacity: 89.5 J = 5.10g x 0.45 J/g°C x (75°C-36°C).
An example of a substance with low specific heat is metal, such as iron or aluminum. These materials heat up quickly when exposed to heat and cool down quickly as well, due to their low specific heat capacity.
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
it depends on the units of the specific heat, but if they are J / goC then you would take your delta T (25-20) and multiply it by your mass (14g) and multiply by your specific heat. In this case it would be 5 * 14 * .11 = 7.7 (with whatever units of energy your specific heat is in.) Just make sure your units cancel out and you will get it right!
yes
Water has a greater specific heat capacity.
The mass is 55.85 and you can find the mass of iron on a periodic table.