The closest match in my (rather old) reference is K40, with a half life of 1.248x109 years. But precision was lacking in the question.
The time it takes for half the atoms in a sample of a radioactive element to decay is called the half life.
The term is called half-life. It is the time it takes for half of the radioactive nuclei in a sample to decay.
Pu-239 has a half-life of 24,110 years.
No, not all elements have a half-life. Half-life is a property of radioactive elements that undergo decay over time. Non-radioactive elements do not have a half-life because they do not decay in the same way.
The time it takes for half of a radioactive sample to decay is known as the half-life. Each radioactive element has a unique half-life, which could range from fractions of a second to billions of years. The half-life remains constant regardless of the size of the initial sample.
1939K is stable and non-radioactive. It, therefore, has no half-life.
In chemistry, the half-life of a reaction is defined as the time needed for the concentration of a reactant to decrease to half of its initial concentration. According to that definition, the half-life of the reaction will be t1/2 = 0,693/k where k is the equilibrium constant for that reaction at a specific temperature.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
dA/dt=-KA A=A0e^-Kt when A=0.5* A0 0.5=e^-K*t half-life 0.693/K=t (1/2) Radiative dating Parent to daughter. Parent should be abundant, daughter should be rare. Most methods used for 10 half life.
The half-life of the reaction ( \text{C}_2\text{H}6(g) \rightarrow 2\text{CH}3(g) ) depends on the order of the reaction. For a first-order reaction, the half-life is constant and can be calculated using the formula ( t{1/2} = \frac{0.693}{k} ), where ( k ) is the rate constant. If the reaction is second-order, the half-life depends on the initial concentration, calculated using ( t{1/2} = \frac{1}{k[\text{C}_2\text{H}_6]^0} ). Thus, without specific rate constants or concentration values, the exact half-life cannot be determined.
For a zero order reaction, the half-life is calculated using the equation: t1/2 = [A]0 / 2k, where [A]0 is the initial concentration of the reactant and k is the rate constant of the reaction. The half-life is independent of the initial concentration of the reactant in zero order reactions.
Second order. If the half life of a reaction is halved as the initial concentration of the reactant is doubled, it means that half life is inversely proportional to initial concentration for this reaction. The only half life equation that fits this is the one for a second-order reaction. t(1/2) = 1/[Ao]k As you can see since k remains constant, if you double [Ao], you will cause t(1/2) to be halved.
K. D. Pillay has written: 'A Seychellois Tamil's half a century of experiences in Seychelles' -- subject(s): Social life and customs, Businesspeople, Biography
To determine the remaining mass of a 10-gram sample of (^{42}\text{K}) after 12.4 hours, we need to know its half-life. The half-life of (^{42}\text{K}) is approximately 12.36 hours. After 12.4 hours, which is slightly more than one half-life, the mass will be reduced to about half of the initial mass. Thus, approximately 5 grams of the original 10-gram sample will remain unchanged after 12.4 hours.
1.5 k
1/2k + 6 or 0.5k + 6
k/2 + 6