The closest match in my (rather old) reference is K40, with a half life of 1.248x109 years. But precision was lacking in the question.
The time it takes for half the atoms in a sample of a radioactive element to decay is called the half life.
I believe that term would be 'half-life'
A "Half-Life" is not half of a life, it is half of the life, then half of that life, and then half of THAT life, and so on and so on. For example: Rock has a half life of 100 ---> 50 ---> 25 ---> 12.5 ---> 6.25 ---> and so on. You just keep dividing the life it has, by 2. Another Example: If you take a dissolving vitamin, and weigh it (20g), and put it in water for 1 minute, it should dissolve into ALMOST half of its original weight, into 10g. Scientists often use the method of "Half-Life" to measure the age of a rock or rock formation. Sources: Am a student in science class
The length of time depends on the element and isotope, but the point at which half of the sample has decayed is known as the half-life.
The half life is not calculated, but experimentally measured. The half life of Pa 234 is 6,75 hours.
1939K is stable and non-radioactive. It, therefore, has no half-life.
In chemistry, the half-life of a reaction is defined as the time needed for the concentration of a reactant to decrease to half of its initial concentration. According to that definition, the half-life of the reaction will be t1/2 = 0,693/k where k is the equilibrium constant for that reaction at a specific temperature.
Since the reaction is first-order, the half-life is constant and equals ln(2)/k, and the units of k are s-1. In this case, the half-life is ln(2)/(.0000739 s-1) = 9379.529 seconds.
dA/dt=-KA A=A0e^-Kt when A=0.5* A0 0.5=e^-K*t half-life 0.693/K=t (1/2) Radiative dating Parent to daughter. Parent should be abundant, daughter should be rare. Most methods used for 10 half life.
Second order. If the half life of a reaction is halved as the initial concentration of the reactant is doubled, it means that half life is inversely proportional to initial concentration for this reaction. The only half life equation that fits this is the one for a second-order reaction. t(1/2) = 1/[Ao]k As you can see since k remains constant, if you double [Ao], you will cause t(1/2) to be halved.
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k/2 + 6
1.5 k
No. Half Life: Opposing Force does not require neither Half Life nor Half Life: Blue Shift.
k/2 + 6
The time it takes for half the atoms in a sample of a radioactive element to decay is called the half life.
1.5 yearsAfter 1 half-life, half will be remaining: 500 - 250 = 250gAfter 2 half-lives, another half of the amount will decay: 250-125 = 125So in 2 half-lives, you have 125 grams left, which according to your problem took 3 years. So in three years you had 2 half-lives occur, therefore the half-life of the isotope is 3 yrs/2 or 1.5 years. Hope that makes sense.-----------------------------You can also solve it mathematically using the decay formula:At = A0 e-kt , where k is the decay constant defined as k = ln 2 / t1/2 (half-life)Ao = amount initially, or 500 gAt = amount after some period of time, in this case 3 years, so At = 125 gt = time elapsed or 3 yearsSubstitute the numbers in the formula and solve for k125 = 500 e-3ke-3k = 125/500ln {e-3k = 0.25}-3k = ln (0.25)k = ln (0.25)/-3substitute into decay constant formula for k to calculate half-life:t1/2 = ln 2 / k= - ln(2)/[ln(0.25)*3]t1/2 = 1.5 yrs