that I'm never gonna give you up,
never gonna let ou down,
never gonna run around and desert you.
Never gonna make you cry,
never gonna say goodbye,
never gonna tell a lie and hurt you.
Speed is scalar (it doesn't have direction), and the magnitude of velocity (a vector). The first derivative of velocity is acceleration, therefore the first derivative of speed is the magnitude of acceleration.
To find the average acceleration over the first 5.1 seconds of motion, divide the change in velocity over that time period by the time taken. Calculate the final velocity minus the initial velocity over 5.1 seconds to find the average acceleration.
To find the acceleration, we first calculate the change in velocity: 4 m/s - 54 m/s = -50 m/s. Next, we use the formula for acceleration: acceleration = change in velocity / time = -50 m/s / 0.75 s = -66.67 m/s^2. The magnitude of the acceleration is 66.67 m/s^2.
In the first 2 seconds, the velocity of the ball would be given by v = at, where a is the acceleration. Given it traveled 2 meters in 2 seconds, we can use the equation s = (1/2)at^2 to find the acceleration which is 1 m/s^2. So, after 3 seconds, the ball will travel an additional 3 * 1 = 3 meters.
0.034 m/s/s
Speed is scalar (it doesn't have direction), and the magnitude of velocity (a vector). The first derivative of velocity is acceleration, therefore the first derivative of speed is the magnitude of acceleration.
1.63 m/s2
To find the average acceleration over the first 5.1 seconds of motion, divide the change in velocity over that time period by the time taken. Calculate the final velocity minus the initial velocity over 5.1 seconds to find the average acceleration.
The magnitude of acceleration depends on the gravitational pull from the planet. The amount of gravitational pull depends on the size and mass of the planet. On Earth gravity will produce an acceleration of 9.8 meters per second squared if there was no atmosphere.
To find the acceleration, we first calculate the change in velocity: 4 m/s - 54 m/s = -50 m/s. Next, we use the formula for acceleration: acceleration = change in velocity / time = -50 m/s / 0.75 s = -66.67 m/s^2. The magnitude of the acceleration is 66.67 m/s^2.
-- First of all, you calculate the magnitude and direction of vectors. An object or a truck are not vectors. Things like their weight, velocity, and acceleration are. -- There are different methods and formulas for calculating each different vector. For example: . . . The truck's weight is (the truck's mass) x (the acceleration of gravity) downward . . . The truck's acceleration is (the rate at which its speed changes) in the direction in which its speed changes.
Acceleration = (change in speed) divided by (time for the change).From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .There's no way that this is happening on the moon. That acceleration is about 67% greaterthan the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.I see the problem now. The '49' in the question should be '4.9'.apex- 1.63 m/s2
I would imagine that it is uniform acceleration up until terminal speed. However, wind resistance will be higher 10000 feet up, so acceleration may be less at the start
If it's ONLY during acceleration I'd check the CV joints first.
In the first 2 seconds, the velocity of the ball would be given by v = at, where a is the acceleration. Given it traveled 2 meters in 2 seconds, we can use the equation s = (1/2)at^2 to find the acceleration which is 1 m/s^2. So, after 3 seconds, the ball will travel an additional 3 * 1 = 3 meters.
0.034 m/s/s
490 meters