that I'm never gonna give you up,
never gonna let ou down,
never gonna run around and desert you.
Never gonna make you cry,
never gonna say goodbye,
never gonna tell a lie and hurt you.
Speed is scalar (it doesn't have direction), and the magnitude of velocity (a vector). The first derivative of velocity is acceleration, therefore the first derivative of speed is the magnitude of acceleration.
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
First calculate the acceleration: the magnitude of circular acceleration is velocity2/ radius.Then use Newton's Law: force = mass x acceleration.
490 meters
Acceleration increases the velocity. There are two physics formulas that you can use to see more how they interact. The first is a formula for determining your current velocity at a given moment t, knowing your initial velocity and your current acceleration. v = v0 + at (v0 is v-naught. The zero is usually written as a subscript.) You can solve this equation for a to get a formula for acceleration as well. a = (v-v0)/t So, basically, at any given interval t, the acceleration has been added onto the current velocity that many times.
Speed is scalar (it doesn't have direction), and the magnitude of velocity (a vector). The first derivative of velocity is acceleration, therefore the first derivative of speed is the magnitude of acceleration.
1.63 m/s2
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
The magnitude of acceleration depends on the gravitational pull from the planet. The amount of gravitational pull depends on the size and mass of the planet. On Earth gravity will produce an acceleration of 9.8 meters per second squared if there was no atmosphere.
-- First of all, you calculate the magnitude and direction of vectors. An object or a truck are not vectors. Things like their weight, velocity, and acceleration are. -- There are different methods and formulas for calculating each different vector. For example: . . . The truck's weight is (the truck's mass) x (the acceleration of gravity) downward . . . The truck's acceleration is (the rate at which its speed changes) in the direction in which its speed changes.
Acceleration = (change in speed) divided by (time for the change).From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .There's no way that this is happening on the moon. That acceleration is about 67% greaterthan the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.I see the problem now. The '49' in the question should be '4.9'.apex- 1.63 m/s2
If it's ONLY during acceleration I'd check the CV joints first.
I would imagine that it is uniform acceleration up until terminal speed. However, wind resistance will be higher 10000 feet up, so acceleration may be less at the start
985kg
For apparent magnitudes, a magnitude of zero has the same magnitude as Vega. A first magnitude star is 40 percent as bright and a fifth magnitude star is one percent. So, a first magnitude star is 40 times as bright as a fifth.
Increasing.
First, convert the speeds to SI units, that is, to meters/second. Then, simply subtract the difference in speed by the 2 seconds. The result will be in meters/sec2.