The area under a displacement over force graph represents work done. It indicates the amount of energy transferred when a force acts over a particular displacement.
The area under a force-distance graph represents the work done. It is equal to the force applied multiplied by the distance moved in the same direction as the force.
On a graph showing the motion of an object, variables such as time (on the x-axis) and position or displacement (on the y-axis) would be used. The slope of the graph would represent the object's velocity, while the area under the curve would represent the object's displacement.
The work done is equal to the area under the curve on a force versus displacement graph. To find the work, calculate the area of the shape(s) represented by the graph. This can be done by breaking down the shape into simpler geometrical shapes and calculating their areas.
The force-displacement graph for the strings of a new type of graphite-head tennis racquet is shown in diagram (a). The racquet is tested in a laboratory by being secured vertically and then having a special type of non-deforming tennis ball fired at it horizontally, as shown in diagram (b). The initial velocity of the ball as it strikes the racquet is 10 m s-1 east. After striking the racquet, the ball has a velocity of 9.5 m s-1 west. The mass of the ball is 100 g. What is the maximum displacement of the strings of the racquet during this interaction?
To calculate displacement from a displacement graph, find the area under the curve. If the graph is a straight line, you can subtract the initial position from the final position. If the graph is not a straight line, calculate the integral of the graph to determine the total displacement.
Work done by the force.
It is the work done or the energy utilised
The area under a force-distance graph represents the work done. It is equal to the force applied multiplied by the distance moved in the same direction as the force.
On a graph showing the motion of an object, variables such as time (on the x-axis) and position or displacement (on the y-axis) would be used. The slope of the graph would represent the object's velocity, while the area under the curve would represent the object's displacement.
Displacement is the area under the v-t graph.
It represent the distance covered is 40 metre.
The work done is equal to the area under the curve on a force versus displacement graph. To find the work, calculate the area of the shape(s) represented by the graph. This can be done by breaking down the shape into simpler geometrical shapes and calculating their areas.
The force-displacement graph for the strings of a new type of graphite-head tennis racquet is shown in diagram (a). The racquet is tested in a laboratory by being secured vertically and then having a special type of non-deforming tennis ball fired at it horizontally, as shown in diagram (b). The initial velocity of the ball as it strikes the racquet is 10 m s-1 east. After striking the racquet, the ball has a velocity of 9.5 m s-1 west. The mass of the ball is 100 g. What is the maximum displacement of the strings of the racquet during this interaction?
To calculate displacement from a displacement graph, find the area under the curve. If the graph is a straight line, you can subtract the initial position from the final position. If the graph is not a straight line, calculate the integral of the graph to determine the total displacement.
The displacement, along the direction of measurement, is zero. It need not mean that the object is back at the starting point. The displacement-time graph, measuring the vertical displacement of a ball thrown at an angle, will have displacement = 0 when the ball returns to ground level but, unless you are extremely feeble, the ball will be some distance away, not at its starting point which is where you are. The use of such a graph is not unusual in the elementary projectile motion under gravity.
A displacement-time graph is a visual representation that shows how an object's position changes over time. The slope of the graph indicates the object's velocity, while the area under the graph corresponds to the total distance traveled by the object.
To find the displacement from a negative velocity-time graph, you need to calculate the area under the curve for the portion representing displacement. If the velocity is negative, the displacement will be in the opposite direction. The magnitude of the displacement is equal to the absolute value of the area under the curve.