Doubling the area of a conductor reduces the resistance by half. This is because resistance is inversely proportional to the cross-sectional area of the conductor. Therefore, doubling the area reduces the resistance, making the conductor more efficient in conducting electricity.
If the area is doubled while keeping the force constant, the pressure exerted by the force will be halved. This is because pressure is defined as force divided by area, so doubling the area will result in a decrease in pressure.
If the length of the conductor increases while the cross-sectional area remains unchanged, the resistance of the conductor will increase. This is because resistance is directly proportional to length according to the formula R = ρ * (L/A), where ρ is the resistivity of the material, L is the length, and A is the cross-sectional area.
Conductor area refers to the cross-sectional area of a conductor, such as a wire or cable, that carries an electric current. It is typically measured in square millimeters or square inches and is an important factor in determining the current-carrying capacity and resistance of the conductor. A larger conductor area generally allows for more current to flow with lower resistance.
As the cross-sectional area of a conductor increases, its resistance decreases. This is because a larger area allows more electrons to flow through the conductor, reducing congestion and increasing conductivity. Consequently, the larger cross-sectional area decreases the resistance to the flow of current.
Doubling the surface area on which a force is being exerted reduces the pressure by half. This is because pressure is force divided by surface area. So, if the force remains the same while the surface area doubles, the pressure decreases.
Doubling the diameter of a circular-section conductor will quadruple its cross-sectional area and, therefore, reduce its resistance by a quarter. Doubling the length of a conductor will double its resistance. So, in this example, the resistance of the conductor will halve.
Resistance is inversely-proportional to the cross-sectional area of a conductor. For example, doubling its cross-sectional area will halve its resistance, while halving its cross-sectional area will double its resistance.Since the cross-sectional area of a circular-section conductor is proportional to the square of its radius, doubling that radius will reduce its resistance by one quarter, while halving its radius will quadruple its resistance.
doubles
Low resistance.AnswerSince resistance is inversely proportional to the cross-sectional area of a conductor, increasing the diameter ('thickness') of a conductor will reduce its resistance.For example, doubling the diameter of a circular-section conductor will quadruple its cross-sectional area, and reduce its resistance by one quarter.
Resistance will decreases... Because R is inversely proportional to Area of the conductor.AnswerIf the conductor has a circular cross-sectional area, then doubling the diameter will reduce the resistance to one quarter of its original distance. This is because area is proportional to the square of the radius, and resistance is inversely proportional to cross-sectional area.
Denote the original area by A, denote the new area by A', denote the original circumference by C, and denote the new circumference by C'. C=2*pi*r so C'=2C=2*pi*(2r). So doubling the circumference corresponds to doubling the radius. A=pi*r2. A'/A=pi*(2r)2/[pi*r2]=4. So doubling the radius quadruples the area.
As the area of a circle A equals pi times the radius squared, and doubling the diameter means multiplying the radius by four, the area is multiplied by 16 when you double the diameter.
If the area is doubled while keeping the force constant, the pressure exerted by the force will be halved. This is because pressure is defined as force divided by area, so doubling the area will result in a decrease in pressure.
Doubling the base of a triangle while keeping the height constant will double the area of the triangle. The area of a triangle is directly proportional to its base length, so increasing the base length by a factor of 2 will result in the area being multiplied by 2 as well.
Four.
If you double them all it will be 4 times the area
The resistance of a conductor is directly proportional to its length, hence increasing the length twice will increase the resistance twice as well. Therefore the resistance will be 2*10 = 20 Ohms