It's not possible to tell from only that much information.
When you throw a rock up, its acceleration is the acceleration of gravity from
the moment it leaves your hand until it hits the ground. But its velocity is
upward some time, downward some time, and zero at the top.
It doesn't. If acceleration is zero, that just means that velocity isn'tchanging ... the motion is in a straight line at a constant speed.
"Acceleration" means change of velocity. If velocity is constant, then acceleration is zero.
if acceleration is <0 and velocity =0 then you got the handbrake on
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
If the ball is traveling at a constant velocity of 50 m/s, then its acceleration is 0 m/s^2. Acceleration is the rate of change of velocity, so if the velocity is constant, there is no change in velocity, and therefore no acceleration.
It doesn't. If acceleration is zero, that just means that velocity isn'tchanging ... the motion is in a straight line at a constant speed.
"Acceleration" means change of velocity. If velocity is constant, then acceleration is zero.
if acceleration is <0 and velocity =0 then you got the handbrake on
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
Not at all. Zero acceleration just means that the velocity is not changing ...the motion is in a straight line at a consgtant speed.
If the ball is traveling at a constant velocity of 50 m/s, then its acceleration is 0 m/s^2. Acceleration is the rate of change of velocity, so if the velocity is constant, there is no change in velocity, and therefore no acceleration.
It's not. If you speed is constant (but not zero), then your velocity won't be zero, either.You may be confusing this with the following: If your VELOCITY (not your speed) is constant, then your ACCELERATION is zero. Acceleration refers to how quickly velocity changes, so if velocity doesn't change at all, acceleration is zero.
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
No it cannot. It is either one or the other. For constant velocity, acceleration must be 0, meaning there is no acceleration happening here. If there is constant acceleration, then the velocity is constantly changing.
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
The acceleration of the body was zero during this interval because its velocity was constant. Acceleration is the rate of change of velocity, so if the velocity does not change, the acceleration is zero.
Yes.