0
What else can I help you with?
What is acceleration at instantaneous maximum velocity?
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
What is the maximum velocity and acceleration that can be found for a point on the string?
The maximum velocity and acceleration of a point on a string depend on the properties of the string and the forces acting on it. The velocity of a point on the string can be limited by factors such as tension and length of the string. The acceleration of a point on the string can be limited by factors such as the mass of the string and the forces acting on it. The maximum velocity and acceleration can vary depending on the specific situation and conditions.
If an object is moving at a constant velocity what do you know about its acceleration?
"Acceleration" means change of velocity. If velocity is constant, then acceleration is zero.
When velocity is zero and acceleration is less than zero does the speed increase?
if acceleration is <0 and velocity =0 then you got the handbrake on
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
Give example where the velocity of the particle is 0 and acceleration is maximum?
When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum
What is the maximum velocity and maximum acceleration of a particle in SHM in terms of amplitude and omega?
0 velocity
Is a rocking chair related to periodic events?
Yes, the velocity of the chair changes as a simple harmonic motion (SHM) and varies from 0 to maximum back to 0 back to ... The acceleration of the chair also relates to SHM in that it varies inversely with the velocity - high velocity = 0 acceleration, 0 velocity = maximum acceleration. If you chart the speed of the shadow of the chair you will see a smooth waveform - likely a sine wave.
What is acceleration at instantaneous maximum velocity?
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
Is this possible that a body has zero velocity but maximum acceleration?
I'm trying to give you a simple example. Which hope will be able to make you understand that thing. We read physics in our language. So I can make some mistakes to write that in English... But I hope I won't be mistaken. By the way here it is... Suppose, There is a simple oscillator what is moving under the angles of 4 degrees. When it is in his height position then we know that it stops for a moment and then comes back to the equilibrium position. So in the height position it's velocity is 0 m/s. (cause it stops.) Suppose it's 1st velocity or the velocity in the equilibrium position is "v" and in that position the last velocity is 0. so we can calculate it's acceleration like that a = (last velocity-1st velocity)/time so a = (0-u)/t = - u/t, what is the maximum acceleration of a this body, (-) sign means the acceleration is gonna go down. But when it is coming back to the equilibrium position, it's velocity goes up.. And in the equilibrium position it's velocity is maximum. Then the velocity decreases again. so in the equilibrium position the velocity is maximum, in the equilibrium position which is "v". so it's acceleration will be a= v-v/t = 0/t = 0, that means the acceleration is zero when the velocity is maximum... That means the acceleration of a body can be zero when the velocity is maximum and the velocity can be zero when the acceleration is maximum. [Note: Always remember, to start to calculate from the equilibrium position. Because the oscillation starts from the equilibrium position. And what I said is the most simple statement. It can also be described by the equations of the a simple harmonic oscillations] - by JAS
What is the condition for maximum velocity?
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
What is the maximum velocity and acceleration that can be found for a point on the string?
The maximum velocity and acceleration of a point on a string depend on the properties of the string and the forces acting on it. The velocity of a point on the string can be limited by factors such as tension and length of the string. The acceleration of a point on the string can be limited by factors such as the mass of the string and the forces acting on it. The maximum velocity and acceleration can vary depending on the specific situation and conditions.
If an object is moving at a constant velocity what do you know about its acceleration?
"Acceleration" means change of velocity. If velocity is constant, then acceleration is zero.
What is maximum acceleration rate?
the acceleration is equal to energy that release by the friction that came be electic that travel form somewhere.It proves that maximum acceleration rate.The easy explainationof that is Energy and Velocity are equal to maximum of acceleration
When velocity is zero and acceleration is less than zero does the speed increase?
if acceleration is <0 and velocity =0 then you got the handbrake on
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
Does 0 acceleration means 0 velocity?
Not at all. Zero acceleration just means that the velocity is not changing ...the motion is in a straight line at a consgtant speed.
