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Depending on its weight:

the amount of work done: A

its weight: M

free falling body: Vi = 0

A = F.d ( Force x Distance ) = E(initial) - E(Final) = MgH(initial) - MgH(final)

H is the height

A = MgH with H = 1 m ... A = Mg joules

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What are the examples of freely falling bodies?

Examples of freely falling bodies include an apple falling from a tree, a skydiver jumping out of a plane, and a rock dropped from a cliff. These objects fall under the influence of gravity with only the force of gravity acting upon them.


How equation of motion are modified for freely falling objects?

For freely falling objects, the equation of motion is modified to account only for the effects of gravity. The equation becomes: y = 0.5gt^2, where y is the height of the object at time "t" in seconds, and "g" is the acceleration due to gravity (approximately 9.8 m/s^2). Friction and other forces are typically ignored in these scenarios.


How are height distance and speed related?

Now, this is in very....basic. It also may not be 100% correct. The higher up you are, the more distance you fall. The more distance you fall, the faster you go. You peak at a certain speed, and will continue falling at that speed once it is reached. The max speed differs in the amount of weight falling. (Proven by an Egg falling, or a Feather falling.)


What is the formula for calculating the velocity of an object falling freely under gravity, considering the acceleration due to gravity as 2g?

The formula for calculating the velocity of an object falling freely under gravity, considering the acceleration due to gravity as 2g, is v (2gh), where v is the velocity, g is the acceleration due to gravity, and h is the height from which the object falls.


How do you increase the time of descent of a freely falling body?

You can increase the time of descent of a freely falling body by increasing its initial height from which it falls. This will give it more distance to cover before reaching the ground, thereby increasing the time it takes to fall. Additionally, you can increase air resistance by changing the shape or size of the falling object, which will also increase the time of descent.

Related Questions

What are the examples of freely falling bodies?

Examples of freely falling bodies include an apple falling from a tree, a skydiver jumping out of a plane, and a rock dropped from a cliff. These objects fall under the influence of gravity with only the force of gravity acting upon them.


How equation of motion are modified for freely falling objects?

For freely falling objects, the equation of motion is modified to account only for the effects of gravity. The equation becomes: y = 0.5gt^2, where y is the height of the object at time "t" in seconds, and "g" is the acceleration due to gravity (approximately 9.8 m/s^2). Friction and other forces are typically ignored in these scenarios.


How are height distance and speed related?

Now, this is in very....basic. It also may not be 100% correct. The higher up you are, the more distance you fall. The more distance you fall, the faster you go. You peak at a certain speed, and will continue falling at that speed once it is reached. The max speed differs in the amount of weight falling. (Proven by an Egg falling, or a Feather falling.)


What is the formula for calculating the velocity of an object falling freely under gravity, considering the acceleration due to gravity as 2g?

The formula for calculating the velocity of an object falling freely under gravity, considering the acceleration due to gravity as 2g, is v (2gh), where v is the velocity, g is the acceleration due to gravity, and h is the height from which the object falls.


How do you increase the time of descent of a freely falling body?

You can increase the time of descent of a freely falling body by increasing its initial height from which it falls. This will give it more distance to cover before reaching the ground, thereby increasing the time it takes to fall. Additionally, you can increase air resistance by changing the shape or size of the falling object, which will also increase the time of descent.


What is the acceleration of a freely falling object 2 seconds after it has been released from height of M?

The acceleration of a freely falling object is approximately 9.81 m/s^2, directed downwards towards the center of the Earth. Therefore, the acceleration of the object 2 seconds after being released will still be 9.81 m/s^2, assuming no other forces are acting on it.


What variables influence the amount of potential energy a falling object has?

Mass of the object, height, and gravitational force. On Earth, Potential Energy = (mass) x (height) x (9.8 m/s)


At what height is falling into water fatal?

Falling into water from a height of around 50 feet or higher can be fatal due to the impact on the body.


What is the kinetic energy for freely falling body at the ground level?

The kinetic energy of a freely falling body at ground level is equal to its potential energy at the starting height, assuming no air resistance or other external forces are acting on it. The kinetic energy is given by ( KE = \frac {1}{2} m v^2 ), where (m) is the mass of the object and (v) is its velocity just before hitting the ground.


How is gravity different for objects that freely fall down and those thrown upwards?

The gravity acting on a rising object and that on a falling object are the same when these objects are at the same height. What is different is that a rising object is decelerating by the force of gravity and the falling object is accelerating.


What is a rush of water falling from a height?

A waterfall


How long does it take to reach terminal velocity when falling from a height?

Terminal velocity is typically reached within 10-12 seconds when falling from a height, depending on factors such as air resistance and the height of the fall.