Apparent weight = Fg - Fb = 1256 - 1562 = -306 N
so in this case buoyance force is greater than its real weight so it must be rising to the water surface and floats.
if its floating, its zero : weight or force = upthrust from water note: upthrust from water = weight of water displaced
Archimedes principle states that any immersed body in a fluid will experience a buoyant force which is equal to the weight of fluid displaced by it and always acts upwards through the centroid of displaced volume. Note that if the object weight less than the wieght of water it displaces, it will float. If it is heavier than the weight of water it displaces, it will sink but its apparent weight in water will be its in-air weight minus the weight of the water it displaces.
200 N
It displaces 12/9.8 kg of water = 1.22 Kg. This would be assuming that gravity is 9.8 M/S2
The science is called "displacement". If the shape of the boat allows the amount of the boat in the water to be less weight than the water it displaces it will float. If the amount of the boat in the water weighs more than the water it displaces it will sink.
You haven't asked a question. So I'll ask one using your data, and then answer it. Q: What is the apparent weight of the object when it's completely submerged ? A: 5 N.
It's 6 kN because the loss of weight equals the weight that has been displaced, i.e. 7 - 1 = 6.
I assume you mean "What happens if the weight of an object is greater than the weight of the water it displaces." If so, the answer is simple, it sinks. If an objects weighs less than the weight of the water it displaces, it floats.
if its floating, its zero : weight or force = upthrust from water note: upthrust from water = weight of water displaced
A submarine has tanks that are called ballast tanks. When these tanks are flooded with sea water, the submarine sinks because the sub weighs more than the water it displaces. To rise again, the sub reduces its weight by pushing compressed air into the ballast tanks. The air forces the sea water out and sub returns to the surface. It maneuvers using its rudder and planes. A link is provided.
Archimedes principle states that any immersed body in a fluid will experience a buoyant force which is equal to the weight of fluid displaced by it and always acts upwards through the centroid of displaced volume. Note that if the object weight less than the wieght of water it displaces, it will float. If it is heavier than the weight of water it displaces, it will sink but its apparent weight in water will be its in-air weight minus the weight of the water it displaces.
Archimedes principle states that any immersed body in a fluid will experience a buoyant force which is equal to the weight of fluid displaced by it and always acts upwards through the centroid of displaced volume. Note that if the object weight less than the wieght of water it displaces, it will float. If it is heavier than the weight of water it displaces, it will sink but its apparent weight in water will be its in-air weight minus the weight of the water it displaces.
200 N
200 N
200 N
It displaces 12/9.8 kg of water = 1.22 Kg. This would be assuming that gravity is 9.8 M/S2
Any object surrounded by a fluid is buoyed up by a force equal to the weight of the fluid it displaces. There's an upward force on a cork in water that's equal to the weight of the water it displaces. There's an upward force on a helium balloon that's equal to the weight of the air it displaces. It so happens that a balloon full of helium weighs less than the air it displaces, so the upward force on it is greater than its weight.