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What is the net force on a rock that weighs 500 N if the weight of the water it displaces is 300 N?
Wiki User
∙ 10y ago
200 N
Wiki User
∙ 10y ago
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What is the weight of water displaced by the nearly massless 1 liter balloon?
Whatever the actual weight of the balloon is, if you just set it on the water, then it displaces an amount of water whose weight is equal to the balloon's weight, and then it sits there and stops displacing. Just like any other floating object. If you force the balloon completely underwater by 'helping' it with added force, then it displaces 1 liter of water, which weighs 9.8 newtons (2.205 pounds).
If an object weighs 20 n it displaces a volume of water that weighs 15 n What is the bouyant force of the object?
According to Archimedes principle...An object immersed in water experiences a force equal to the weight of the volume of liquid displaced by it. Here the weight of liquid displaced is 15n. So, the upward buoyant force experienced by that object is 15n.
What is the apparent weight of a submarine that weighs 1256N and it displaces 1562N of water?
Apparent weight = Fg - Fb = 1256 - 1562 = -306 N so in this case buoyance force is greater than its real weight so it must be rising to the water surface and floats.
What is the apparent weight for a body floating in water equal to?
if its floating, its zero : weight or force = upthrust from water note: upthrust from water = weight of water displaced
A toy boat weighs 12 newtons What is the weight of the water it displaces when it floats?
It displaces 12/9.8 kg of water = 1.22 Kg. This would be assuming that gravity is 9.8 M/S2
What is the net force of a rock that weighs 500 N if the weight of the water it displaces is 300 N?
200 N
Why does a helium balloon rise higher than an air balloon?
Any object surrounded by a fluid is buoyed up by a force equal to the weight of the fluid it displaces. There's an upward force on a cork in water that's equal to the weight of the water it displaces. There's an upward force on a helium balloon that's equal to the weight of the air it displaces. It so happens that a balloon full of helium weighs less than the air it displaces, so the upward force on it is greater than its weight.
What happends if the weight of an object is greather than the weight of the water?
I assume you mean "What happens if the weight of an object is greater than the weight of the water it displaces." If so, the answer is simple, it sinks. If an objects weighs less than the weight of the water it displaces, it floats.
What is the weight of water displaced by the nearly massless 1 liter balloon?
Whatever the actual weight of the balloon is, if you just set it on the water, then it displaces an amount of water whose weight is equal to the balloon's weight, and then it sits there and stops displacing. Just like any other floating object. If you force the balloon completely underwater by 'helping' it with added force, then it displaces 1 liter of water, which weighs 9.8 newtons (2.205 pounds).
If an object weighs 20 n it displaces a volume of water that weighs 15 n What is the bouyant force of the object?
According to Archimedes principle...An object immersed in water experiences a force equal to the weight of the volume of liquid displaced by it. Here the weight of liquid displaced is 15n. So, the upward buoyant force experienced by that object is 15n.
What is the apparent weight of a submarine that weighs 1256N and it displaces 1562N of water?
Apparent weight = Fg - Fb = 1256 - 1562 = -306 N so in this case buoyance force is greater than its real weight so it must be rising to the water surface and floats.
What is the apparent weight for a body floating in water equal to?
if its floating, its zero : weight or force = upthrust from water note: upthrust from water = weight of water displaced
A toy boat weighs 12 newtons What is the weight of the water it displaces when it floats?
It displaces 12/9.8 kg of water = 1.22 Kg. This would be assuming that gravity is 9.8 M/S2
The buoyant force on an object is equal to the weight of the water it?
The buoyant force on an object is equal to the weight of the water it displaces. This is called Archimedes' principle, which states that "The buoyant force on an object is equal to the weight of the fluid displaced by the object."
Why a rock appears as less weight in water?
Because any object in water is buoyed up by a force equal to the weight of the water it displaces (pushes aside).
What is achimedes principle?
Archimedes principle states that any immersed body in a fluid will experience a buoyant force which is equal to the weight of fluid displaced by it and always acts upwards through the centroid of displaced volume. Note that if the object weight less than the wieght of water it displaces, it will float. If it is heavier than the weight of water it displaces, it will sink but its apparent weight in water will be its in-air weight minus the weight of the water it displaces.
Achimedes ' principle?
Archimedes principle states that any immersed body in a fluid will experience a buoyant force which is equal to the weight of fluid displaced by it and always acts upwards through the centroid of displaced volume. Note that if the object weight less than the wieght of water it displaces, it will float. If it is heavier than the weight of water it displaces, it will sink but its apparent weight in water will be its in-air weight minus the weight of the water it displaces.
