The current is calculated by dividing the charge (6 coulombs) by the time (2 seconds). Therefore, the current is 3 amperes (6 coulombs / 2 seconds = 3 amperes).
Charge flow can be calculated by multiplying the current (in amperes) by the time (in seconds) for which the current flows. The formula is Q = I * t, where Q is the charge flow in coulombs, I is the current in amperes, and t is the time in seconds.
Electric current (in amperes) is calculated by dividing the electrical charge (in coulombs) by the time taken (in seconds) for the charge to pass through a given point in a circuit. The formula is I = Q / t, where I is the current, Q is the charge, and t is the time.
In the formula for electric current (I = q/t), q represents the amount of charge passing through a point in a circuit, measured in coulombs. t represents the time taken for the charge to pass through that point, measured in seconds. Electric current (I) is the rate at which charge flows through a circuit.
The charge that flows through the light bulb can be calculated using the formula Q = I * t, where Q is the charge, I is the current, and t is the time. Therefore, Q = 35A * 4s = 140C. So, 140 coulombs of charge flow through the light bulb in 4 seconds with a current of 35A.
To calculate the time it takes for 9 coulombs to pass a current of 3 amps, you can use the formula: time = charge / current. Plugging in the values, time = 9 coulombs / 3 amps = 3 seconds. So, it would take 3 seconds for 9 coulombs to pass a current of 3 amps.
To calculate the total charge passing through the cell, use the formula Q = I * t, where Q is the charge in coulombs, I is the current in amperes, and t is the time in seconds. First, convert 85.0 minutes to seconds: 85.0 minutes * 60 seconds/minute = 5100 seconds. Then, plug in the values: Q = 2.40 amperes * 5100 seconds = 12240 coulombs.
Divide the coulombs by the amperes. The answer will be in seconds. The resistance is irrelevant in this problem.
A flow of 7400 coulombs in 85 seconds represents a current of 87 amperes. One ampere is one coulomb per second, so divide 7400 by 85.
Current = charge/time = 10/5 = 2 amperes
The charge transferred in 25 minutes by a current of 500 mA is 750 coulombs. Amperes is defined as coulombs per second, so 500 mA is 0.5 coulombs per second. 25 minutes is 1500 seconds, so the charge is 750 coulombs.
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
Charge flow can be calculated by multiplying the current (in amperes) by the time (in seconds) for which the current flows. The formula is Q = I * t, where Q is the charge flow in coulombs, I is the current in amperes, and t is the time in seconds.
Electric current (in amperes) is calculated by dividing the electrical charge (in coulombs) by the time taken (in seconds) for the charge to pass through a given point in a circuit. The formula is I = Q / t, where I is the current, Q is the charge, and t is the time.
10/2 = 5 coulombs per second = 5 amperes.
Current in amperes is coulombs per second, so 2 coulombs per second is 2 amperes.
If you divide the charge by the time, you get the average current (in amperes).
In the formula for electric current (I = q/t), q represents the amount of charge passing through a point in a circuit, measured in coulombs. t represents the time taken for the charge to pass through that point, measured in seconds. Electric current (I) is the rate at which charge flows through a circuit.