232Th --> 228Ra + 4He
228Ra --> 228Ac + e-
228Ac --> 228Th + e-
228Th --> 224Ra + 4He
224Ra --> 220Rn + 4He
220Rn --> 216Po + 4He
216Po --> 212Pb + 4He
212Pb --> 212Bi + e-
212Bi --> 208Tl + 4He, 212Po + e-
208Tl --> 208Pb + e-
212Po --> 208Pb + 4He
208Pb, stable
Other isotopes of Thorium undergo beta decay, but they are not naturally occurring.
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The possible products of the alpha decay of uranium-238 are thorium-234 and helium-4. During alpha decay, the uranium nucleus releases an alpha particle (helium nucleus) and transforms into thorium-234.
The equation for alpha decay of thorium-228 is 228Th -> 224Ra + 4He, where thorium-228 decays into radium-224 by emitting an alpha particle (helium nucleus). The equation for beta decay of aluminum-28 is 28Al -> 28Si + e + v, where aluminum-28 decays into silicon-28 by emitting a beta particle (electron) and an antineutrino.
The natural isotope 227Ac decay: - by beta minus decay: to 227Th - by alpha decay: to 223Fr
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
What is missing is the type of decay that occurs during the transformation. For example, uranium-238 decays into thorium-234 through alpha decay, so the missing component would be the emission of an alpha particle in the balanced equation.
The decay equation for uranium-238 (U-238) decaying into an alpha particle (helium-4) can be represented as follows: (^{238}{92}\text{U} \rightarrow ^{4}{2}\text{He} + ^{234}_{90}\text{Th}). This equation shows the radioactive decay process of U-238 into an alpha particle and thorium-234.
alpha
By alpha decay Th-230 is transformed in Ra-226.
The decay of thorium by alpha decay the resultant nuclide is the element radium. The specific nuclide of radium cannot be determined unless we know which specific nuclide of thorium underwent alpha decay.
daughter element
Uranium 238 is transformed in thorium 234 by alpha decay.
The two elements that undergo alpha decay are uranium and thorium.
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
It is thorium 234.