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Divide the speed of light in a vacuum (in meters/second) by the wavelength (which you must convert to meters); that will give you the frequency in hertz. The frequency will be the same for different substances.

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Q: What is the frequency of light in fused quartz if the wavelength in vacuum is 500nm?
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Does 300nanometers have a lower frequency than 500nanometers?

300nm is the "wavelength". Wavelength and frequency are related by the following equation: λ = v / f Where λ (gamma) is the wavelength, v is the speed of the wave (typically c, the speed of light (3×10^8 m/s)), and f is the frequency. So f = v / λ. So a 300nm wave, (λ = 300*10^-9 m) has a frequency of (3e8 / 300e-9) = 1e15Hz or 1,000THz. 500nm: (3e8 / 500e-9) = 6e14Hz or 600THz. See link.


Which has the greater frequency a 300 nm photon or a 500 nm photon?

frequency = 1/s c = m/s lambda = m (wavelength) c/lambda m/s/m= frequency 1/s 300,000E9mm/s / 300nm > 300,000E9nm/s / 500nm So no, the shorter the wavelength, the higher the frequency. This is why very small waves such as gamma waves are very dangerous; they have a very high frequency compared to feet long waves such as Radio waves.


In double slit interference for a wavelength of 500nm the path length difference between the two waves for the second constructive interference fringe is?

1 micrometer (1,000 nm)


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Calculate the limit of resolution for the oil lens of your microscope Assume an average wavelength of 500nm?

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The question makes little sense, but sound is a longitudinal wave, light is a transverse wave. Light avergaes around 500nm wavelength, sound audible to the human ear ranges from a few cm to 20m or so.


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How many waves of 500 nanometers would it take to equal 1 cm?

A 500nm wave has a wave length of 500nm. The nano- prefix means × 10^-9 → 500 nm = 500 × 10^-9 m The centi- prefix means × 10^-2 → 1 cm = 1×10^-2 m → 1 cm ÷ 500 nm = (1×10^-2 m) ÷ (500×10^-9 m) = (1/500) × 10^(-2 - -9) = 0.002 × 10^7 = 2 × 10^4 = 20,000 waves.


What wavelength of visible light is least utilized by chlorophyll?

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