If each student is pushing with a force of 50 newtons in opposite directions, the net force will be the difference between the forces, which would be 0 newtons since they are equal and opposite. So, the net force on the box would be 0 newtons.
If 5 newtons of force are pulling against another 5 newtons of force in opposite directions, there will be a net force of 0 newtons, resulting in no movement or acceleration. The forces are balanced and cancel each other out.
The person pulling with 600 newtons of force would overpower the person pulling with 500 newtons of force. The resulting net force would be 100 newtons in the direction of the person with the higher force.
As always, that's going to depend on where he is. Wherever it is, the forces of gravity between him and another nearby mass will both be (45 kg) x (acceleration of gravity in the vicinity of the other mass). If the other mass is the Earth, then the acceleration of gravity is 9.8 m/s2 , and the force, which the student will call his 'weight', is (45) (9.8) = 441 newtons (99.21pounds / 7stone 1.21pounds)
That depends on the gravity. On Earth, each kilogram weighs about 9.8 Newton.
Gravity (acceleration) is equal to Force divided by mass. So, 126 / 15 = 8.4m/s^2
If 5 newtons of force are pulling against another 5 newtons of force in opposite directions, there will be a net force of 0 newtons, resulting in no movement or acceleration. The forces are balanced and cancel each other out.
The person pulling with 600 newtons of force would overpower the person pulling with 500 newtons of force. The resulting net force would be 100 newtons in the direction of the person with the higher force.
If each horse is pulling with 100 newtons of force, then this is a balanced force system in a Static State.
As always, that's going to depend on where he is. Wherever it is, the forces of gravity between him and another nearby mass will both be (45 kg) x (acceleration of gravity in the vicinity of the other mass). If the other mass is the Earth, then the acceleration of gravity is 9.8 m/s2 , and the force, which the student will call his 'weight', is (45) (9.8) = 441 newtons (99.21pounds / 7stone 1.21pounds)
That depends on the gravity. On Earth, each kilogram weighs about 9.8 Newton.
Gravity (acceleration) is equal to Force divided by mass. So, 126 / 15 = 8.4m/s^2
f=force, m=mass, a=acceleration
Take the sum of the forces on the object on the horizontal plane(x-direction) with the positive direction being to the right. The 80 newtons to the right is +80N and the 80 newtons acting to the left is -80N. Add them up, so 80N - 80N = 0 N. The total force acting on the object is 0.
The tension in the rope will be 100 Newtons. Each force of 100 Newtons will act in opposite directions on the rope, resulting in an equal tension force along the length of the rope.
Newtons and kilograms really measure different things (force versus mass). But if you assume normal Earth gravity, each kilogram has a weight of 9.8 Newtons. In this case, you can convert newtons to kilograms, dividing by 9.8.
Fnet = F1+F2Force of man f1 = 10nForce of goat f2 = 10nSo,Fnet = 10+10Fnet=20n================================-- If Fred and the man are both pushing in the same direction, thenthe net force is 20 newtons.-- If they're not both pushing in the same direction, then the net forceis less than 20 N, but we don't have enough information to be able tonail down either the net force or its direction.
F=ma, Force=(mass)(Accleration), (3)(1250)-(3)(200)= 3,150 Newtons