What is the nuclear equation for the beta decay of titanium-50?

Answer 1

It turns out that titanium (Ti) has several stable isotopes, including Ti-50. Ti-50 doesn't naturally decay, so we won't see the beta decay of Ti-50 in the literature. If it did, it could decay in one of two ways, because there are two different "flavors" or beta decay. One decay mode is beta minus decay, and here we see a neutron is converted into a proton through the mediation of the weak interaction (weak nuclear force). In this process, an electron and an antineutrino are ejected from the nucleus. In beta plus decay, a proton is converted into a neutron, again through the mediation of the weak interaction. A positron (an anti-electron) and a neutrino are ejected from the nucleus in this process. Here's how the equations would look if the reactions were possible: For beta minus decay, 2250Ti => 2350V + e- + ve- In this case, the titanium atom is transmuted into another element, vanadium (V). This is because the number of protons in the nucleus of the atom has increased by one. For beta plus decay, 2250Ti => 2150Sc + e+ + ve+ In this case, the titanium atom is transmuted into another element, scandium (Sc). This is because the number of protons in the nucleus has decreased by one. These are the basic formulae for beta decay, and both types (beta + and beta -) are presented. You can (should) be able to write any others using this example and by thinking about it just a bit and consulting the Periodic Table of elements. Links can be found below for confirmation of facts and the acquisition of more information.

Answer 2

50Ti22 yields 50V23 + 0e-1

Note:

1) The mass numbers (the superscripts) are usually written on the same side as the atomic numbers (subscripts) i.e both are usally to the right of the symbol.

2) I wrote yields since I was not sure how to insert an arrow!

Answer 3

For the beta decay of titanium-50, the nuclear equation would be: 50Ti --> 50V + 0e-1 + antineutrino. This represents the decay of titanium-50 into vanadium-50, with the emission of a beta particle (electron) and an antineutrino.

Answer 4

The nuclear equation for the beta decay of cadmium is 113 and 48 which is the atomic number is right under 113 and the symbol which is Cd is between them.

Answer 5

22Ti44 ----> 21Sc44 + -1e0