That depends on the strength of the electric field, and on the length of time
the electron has been experiencing it.
An electron in an electric field accelerates uniformly.
The relation between electric current and drift velocity is that they both happen to involve electrons moving opposite of the electric field. The electric field must also have a conductor.
Yes some delicate situation. Here we have to take a lot of information into consideration. Actually electrons move at random direction and in the absence of an electric field the net velocity of the electrons will be zero. Hence we can assume the initial velocity to be zero. Now as an electric field is applied then a force of eE is acting on the electron opposite to the field direction. Due to this electrons get accelerated. No doubt about it. But this acceleration is in effect only for a duartion known as relaxation time. Hence the speed picked up will be acceleration x relaxation time. So this velocity attained in that duration is called as Drift velocity. Vd = (eE / m )* t. Here m is mass of electron. Hence a constant velocity Vd
an electron
As we know in klystron tube drift space is assumed to be free of any electric field. Therefore, the high velocity electron emerging in the later period are able to overtake the low velocity electrons leaving the buncher grids. As a result of these actions, the electrons gradually bunch together as they travel down the drift space. This mechanism of variation in electron velocity in the drift space is known as velocity modulation.
Practically speaking electron beam is controlled by magnetic field produced by passing electric current through yoke coil.
Force experienced will be same in magnitude as that of electron but in opp direction i.e. F=qE.
I would say a magnetic field. When an electron enters a magnetic field that is oriented perpendicular to its path of travel it causes the electron to loop in a circle. While the speed stays the same the velocity is constantly changing due to the circular motion. Hence same speed but undergoing an acceleration.
The electric field is stronger near the electron and becomes weaker as the distance from the electron increases.
Stationary charge don't produce a magnetic field. because it has no velocity in it, without flow of electron we can't find electricity and for that we have no magnetic field for a stationary charge. It produce only electric field.
Yes. Stationary electric (electrostatic) fields will act on each other and a force will be developed. If you had a standing electric field and could "beam in" an electron (a la Star Trek), the electron would react at once and move either toward a positive field source or away from a negative field source. The electron would know the field was there the instant it appeared.
east
Yes some delicate situation. Here we have to take a lot of information into consideration. Actually electrons move at random direction and in the absence of an electric field the net velocity of the electrons will be zero. Hence we can assume the initial velocity to be zero. Now as an electric field is applied then a force of eE is acting on the electron opposite to the field direction. Due to this electrons get accelerated. No doubt about it. But this acceleration is in effect only for a duartion known as relaxation time. Hence the speed picked up will be acceleration x relaxation time. So this velocity attained in that duration is called as Drift velocity. Vd = (eE / m )* t. Here m is mass of electron. Hence a constant velocity Vd
The relation between electric current and drift velocity is that they both happen to involve electrons moving opposite of the electric field. The electric field must also have a conductor.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
it is the mass of an electron in the presence of an electric or magnetic field.
an electron
because the electric field of the nucleolus is radially symmetrical. And if you really want to get picky, the electron doesn't move in a circle but occupies a spherical probability continuum with indeterminable position and velocity.