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Just divide the distance by the time.

To know the velocity, you would also need to know in what direction the car travels.

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10y ago

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A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?

Since the equation for time=sqrt(2h/g) set 2 seconds for time and 9.8 for gravity so 2=sqrt(2h/9.8) clear the sqrt by squaring both sides 4= 2h/9.8 9.8*4 =2h (9.8*4)/2 = height. now that you have the height, you can do v=distance/time v=height from the equation prior/2 seconds i hope that works..


If I travel 100 m N in 5 seconds what is my average velocity?

To find the speed, take the distance and divide it by the time. 100m/2h = 50m/hr


If a stone fall from the height of 93mwith the initial velocity of 3 mseccalculate the time taken by stone to reach the groundfinalvelocity?

The time taken for the stone to reach the ground can be calculated using the formula: ( t = \sqrt{{\frac{2h}{g}}} ), where ( h = 93m ) and ( g = 9.8 , m/s^2 ) (acceleration due to gravity). Substituting the values, we get ( t = \sqrt{{\frac{2 \times 93}{9.8}}} \approx 4.32s ). The final velocity of the stone when it reaches the ground can be calculated using the formula: ( v^2 = u^2 + 2gh ), where ( u = 3 m/s ) (initial velocity). Substituting the values, we get ( v = \sqrt{{3^2 + 2 \times 9.8 \times 93}} \approx 42.43 m/s ).


What is the normal transfer case range on hard road surfaces for Humvee?

The normal transfer case range for a Humvee on hard road surfaces is typically 2-wheel drive (2H) or 4-wheel drive (4H). 2H is suitable for regular driving conditions, while 4H is ideal for off-road or low-traction surfaces. It's important to avoid using 4-wheel drive on hard road surfaces to prevent damage to the vehicle's drivetrain.


How fast will a puck slide off a table if the table is 5 ft tall and the puck slides at 2ms?

Neglecting friction, if a puck is sliding at 2 m/s it will still be sliding at 2 m/s when it slides off the table. Immediately before hitting the floor, its velocity in the x-direction will still be 2 m/s but it will have accelerated to a y-velocity of approximately 6.4 m/s, yielding a total speed of 6.6 m/s.