Zero meters
Whether the object is dropped, thrown downwards, thrown upwards, or thrown horizontally, its downward acceleration is the same 9.8 meters per second2. If it's thrown downwards, however, its speed at any instant is greater than the speed at the same instant would be if it had only been dropped, since it has some speed before the acceleration begins.
The ball has maximum potential energy at its highest point, which is at a height of 15 meters when it is thrown into the air.
The maximum height hmax that a ball reaches when thrown into the air is the highest point it reaches before falling back down.
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
Assuming the ball is thrown vertically upwards with no air resistance, the time it takes for the ball to reach a certain height can be calculated using the kinematic equation: ( h = v_i t - \frac{1}{2} g t^2 ), where ( h = 13 ) meters (maximum height), ( v_i = 0 ) (initial velocity), and ( g = 9.81 , \text{m/s}^2 ) (acceleration due to gravity). Solving for ( t ) gives approximately 1.46 seconds.
It depends on the height of the building and also on the direction the object is thrown in (up, down etc.).
1000000 m
Whether the object is dropped, thrown downwards, thrown upwards, or thrown horizontally, its downward acceleration is the same 9.8 meters per second2. If it's thrown downwards, however, its speed at any instant is greater than the speed at the same instant would be if it had only been dropped, since it has some speed before the acceleration begins.
The ball has maximum potential energy at its highest point, which is at a height of 15 meters when it is thrown into the air.
force thrown distance height thrown
The maximum height hmax that a ball reaches when thrown into the air is the highest point it reaches before falling back down.
22.35294117647059
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
Assuming the ball is thrown vertically upwards with no air resistance, the time it takes for the ball to reach a certain height can be calculated using the kinematic equation: ( h = v_i t - \frac{1}{2} g t^2 ), where ( h = 13 ) meters (maximum height), ( v_i = 0 ) (initial velocity), and ( g = 9.81 , \text{m/s}^2 ) (acceleration due to gravity). Solving for ( t ) gives approximately 1.46 seconds.
The body will move: * Because of its initial motion (the question states that it is thrown) * Because of gravity