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Along the line of the accelerating force.

Answer2:

There are in general three gravitational force vectors;

F=[d/dr,DEL] [-mGM/r, cP] = [vp/r -cp/r cos(PR), cdP/dr -DELmGM/r + cDELxP]

1. DEL -mGM/r = vp/r 1R the radial direction centripetal

2. cdP/dr = -cp/r 1P the Tangent vector in direction opposite of momentum P.

3. cDELxP = cp/r sin(PR) 1RxP this vector is perpendicular to the other two unless the other two are parallel, then this is a null vector, sin(PR)=0.

These are the 3 gravitational force vectors.

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