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It really depends on the experimental setup. If you have only a capacitor and a resistance in series, the current discharge from the capacitor will start high, then gradually go down. If you have a capacitor and an inductor in series, the current discharge will start being small, because the inductor will oppose any CHANGE in the current - that's how they work.
What else can I help you with?
Why is the charging time of a capacitor lower than the discharging time?
The charging time of a capacitor is usually lower than the discharging time because during charging, the voltage across the capacitor is increasing from zero to its maximum value, which initially allows a higher current to flow. During discharging, the voltage across the capacitor is decreasing from its maximum value to zero, resulting in a lower current flow. This difference in current flow affects the time it takes for the capacitor to charge and discharge.
What does the area under a current versus time graph show?
In the context of capacitors, the area under a current, I, time, t, graph equals the total charged stored on a capacitor.
How do you calculate inductive time constant?
The inductive time constant (L/R) is calculated by dividing the inductance of the inductor (L) by the resistance of the circuit (R). It represents the time it takes for the current in the circuit to reach approximately 63.2% of its maximum value during the charging or discharging of the inductor.
What does a capacitor do in an air conditioner?
A capacitor in an air conditioner stores and releases electrical energy to help start the compressor and fan motors. It provides the initial surge of electricity needed to get these motors running and helps maintain a steady flow of power during operation. If a capacitor fails, the motor may not start or run efficiently.
Why is a capacitor used in a defibrillator and how does it help in delivering a high-energy shock to the heart during cardiac arrest?
A capacitor is used in a defibrillator to store and release electrical energy quickly. When a high-energy shock is needed to restart the heart during cardiac arrest, the capacitor rapidly discharges the stored energy, delivering a strong electrical pulse to the heart. This helps to restore the heart's normal rhythm and potentially save the person's life.
Why is the charging time of a capacitor lower than the discharging time?
The charging time of a capacitor is usually lower than the discharging time because during charging, the voltage across the capacitor is increasing from zero to its maximum value, which initially allows a higher current to flow. During discharging, the voltage across the capacitor is decreasing from its maximum value to zero, resulting in a lower current flow. This difference in current flow affects the time it takes for the capacitor to charge and discharge.
What will happen if a diode is connected to capacitor?
the diode when forward biased will conduct and during reverse biased condition(generally doring reverse biased condition ckt is open mens no current flows;when register is connected)current flows but during reverse biased condition 1--for sometimes initially current flows due to discharging of capacitor. 2--then ckt will be having no current
The electric device which blocks DC but allows AC is called?
A capacitor is a device which blocks DC, but allows AC. When a capacitor is completely charged it does not allow current to pass through it. Initially when capacitor starts charging it has maximum current which flows and voltage is minimum, during charging current decreases with time and voltage increases. When capacitor is completely charged, it has maximum voltage and minimum current. However the AC has both positive and negative half cycles, during positive half cycle capacitor starts charging but during negative half cycle it discharges, and hence it doesn't get fully charged at AC, and current always flows through it.
Why you use capacitor as a filter in power supply?
capacitor acts as a small battery ,during rectification ac to dc it gets some blank space (no current) to fill this current from capacitor is used.
Why high value resistor should be connected in series with capacitor during charging or discharging process?
A resistor is used to limit current flow through a capacitor.If you did not use the resistor, you could potentially create large currents through the capacitor, damaging it. Capacitors do have current limit ratings - check the specification sheet for the capacitor.Also, in the case of an electrolytic capacitor, if it is generally in a discharged state then it is necessary from time to time to reform it. That process involved slowly charging it, i.e. through a resistor, and then letting it discharge by itself with no or little load. The resistor protects both the capacitor and the voltage source in the case that the capacitor might be shorted.
Explain the Potential across the resistor during the charging and discharging process of the capacitor?
The voltage across a capacitors given as a time constant t= 63% the resistor value multiply buy capacitor value. it doesn't matter if it goes more or less negative it will follow this function
How surge current is produced in a capacitor input filter?
Being that the capacitor appears as a short during the initial charging, the current through the diodes can momentarily be quite high. To reduce risk of damaging the diodes, a surge current limiting resistor is placed in series with the filter and load.
What are the starting and running characteristics of a capacitor-start motor?
Easier to start up. Running remains the same unless it is equipped with a run capacitor too. A run capacitor uses a little less current during run and probably runs a little cooler too.
What does the area under a current versus time graph show?
In the context of capacitors, the area under a current, I, time, t, graph equals the total charged stored on a capacitor.
What happens to the voltage across a capacitor as it discharges?
well to get the answer first know the principle by which a capacitor(consider a capacitor without dielectric) gets charged .let a capacitor with plates p1 and p2 and resistor in parlell are connected to a DC source , when the switch is closed the circuit is in ON state and current starts flowing ,assume the flow of current as the movement of negative charges then the concept would be much clear. assume that p1 is connected with positive terminal of the battery and p2 with the negative terminal ,now as the switch is closed the negative charge on p1 is attracted by the positive terminal of the battery and is driven to the other plate p2 of capacitor.as this process continues charge seperation increases and potential difference starts getting developed and after a very long time the potential diff. across capacitor becomes equal to the applied voltage V. during discharging first of all we short the battery , this mplies that we are short circuiting plates p1 and p2 so again charge redistribution takes place and after a longtime both the plates become electrically nuetral
How can you avoid immediate discharging during intercourse?
By using a condom.
How is the capacitor able to account for AC Ripples?
Ripple Voltage is voltage variation across the load and it is the AC component. To answer this question, consider a Half Wave rectifier with a smoothing capacitor: This rectifier will consist of a sinusoidal voltage source, an ideal diode, a capacitor in parallel with the load. At t=0, the voltage across capacitor = load voltage When the circuit is switched on, the capacitor is fully charged as the sinusoidal source reaches its peak. However, the sinusoidal nature causes the source voltage to decline after reaching the peak. This means that no current will flow through the diode. But the capacitor is still charged. So this will supply current to the load while it discharges. But during the discharging period (till the sinusoidal picks up again), the load voltage is an exponential function = peak voltage *exp-[(t - t')*resistance of load*capacitance] Now a key point is that the pulsating current is flowing through the diode to recharge the capacitor. Because of this constant charge and discharge of the capacitor in the cycle, the load voltage has AC ripples. At the same time load current is never zero and is directly prop to load voltage. The dc component >> ac component and the ripple voltage is greatly reduced by the capacitance esp a large one. You can minimize these by choosing a large capacitance. This is how a capacitor accounts for AC ripples. You can never actually rid these ripples even if you use a full-wave rectifier! Google search half - wave rectifier graphs on the ripples to understand this!! --- Sona
