Resistance increases with the length of a wire because longer wires provide more opposition to the flow of current, resulting in more collisions between electrons and atoms in the material. This increased collisions cause more energy to be lost as heat, which in turn increases the resistance of the wire.
If both the diameter and length of a wire are quadrupled, the resistance of the wire will increase by a factor of 16. This is because resistance is directly proportional to the length of the wire and inversely proportional to the cross-sectional area of the wire, which is determined by the diameter. By quadrupling both, the resistance will increase by 4^2 = 16 times.
Assume that the increase in length is achieved by uniform reduction in the cross-sectional area of the wire. Then an increase in length by 4 times will result in the cross sectional area being reduced to a fifth of it original value. This will increase the resistance to five times its previous value.
You could increase the length of the wire or decrease its thickness to increase resistance in the electric circuit. Both of these changes will hinder the flow of electrons through the wire, resulting in higher resistance.
If a resistive wire is elongated, its resistance will increase. This is because the longer length of wire will result in more collisions between electrons and the wire's atoms, leading to higher resistance. The resistance of a wire is directly proportional to its length.
Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L Now we have R = K * L / pi r^2 Multiplying numerator and denominator by L we get R = K/V * L^2 So resistance is found to be proportional to square of length Hence as length gets increased by 2 times, its resistance value would increase by 4 times.
You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).
If both the diameter and length of a wire are quadrupled, the resistance of the wire will increase by a factor of 16. This is because resistance is directly proportional to the length of the wire and inversely proportional to the cross-sectional area of the wire, which is determined by the diameter. By quadrupling both, the resistance will increase by 4^2 = 16 times.
Assume that the increase in length is achieved by uniform reduction in the cross-sectional area of the wire. Then an increase in length by 4 times will result in the cross sectional area being reduced to a fifth of it original value. This will increase the resistance to five times its previous value.
You could increase the length of the wire or decrease its thickness to increase resistance in the electric circuit. Both of these changes will hinder the flow of electrons through the wire, resulting in higher resistance.
If a resistive wire is elongated, its resistance will increase. This is because the longer length of wire will result in more collisions between electrons and the wire's atoms, leading to higher resistance. The resistance of a wire is directly proportional to its length.
3 times
Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L Now we have R = K * L / pi r^2 Multiplying numerator and denominator by L we get R = K/V * L^2 So resistance is found to be proportional to square of length Hence as length gets increased by 2 times, its resistance value would increase by 4 times.
When the length of the wire increases voltage drop across the wire will occur.There are two factors that can result in voltage drop. One diameter of the wire, two length of the wire.Voltage drop increases with increase in length of wire, whereas voltage drop decreases with increase in diameter (cross section area) of the wire.G.RAOAnswerIf you are asking what happens to the voltage across a length of wire when its length increases, the answer is nothinghappens! The voltage applied to the wire is determined by the supply, not by the load (i.e. the wire).
The resistance of the wire is directly proportional to the length and inversely proportional to the area of cross section. Also it depends on the material of the wire with which it is made. So three factors. Length, area of cross section, material.
Other things being equal, a greater length will result in more resistance.
Temperature, Length of wire, Area of the cross-section of wire and nature of the material.
Increasing the wire gauge from AWG 22 to AWG 26 will increase the wire's resistance because a higher gauge corresponds to a thinner wire. Thinner wires have higher resistance due to increased electrical resistance per unit length. Therefore, a wire with AWG 26 will have higher resistance compared to a wire with AWG 22.